Answer:
Molarity = 0.79 M
Explanation:
Given data:
Mass of KNO₂ = 67 g
Volume of solution = 1 L
Molarity of solution = ?
Solution:
First of all we will calculate the number of moles.
<em>Number of moles = mass/ molar mass</em>
Number of moles = 67 g / 85.10379 g/mol
Number of moles = 0.79 mol
Molarity:
Molarity = number of moles / volume in L
Molarity = 0.79 mol/1 L
Molarity = 0.79 M
Answer:
= 20.82 g of BaCl2
Explanation:
Given,
Volume = 200 mL
Molarity = 0.500 M
Therefore;
Moles = molarity × volume
= 0.2 L × 0.5 M
= 0.1 mole
But; molar mass of BaCl2 is 208.236 g/mole
Therefore; 0.1 mole of BaCl2 will be equivalent to;
= 208.236 g/mol x 0.1 mol
= 20.82 g
Therefore, the mass of BaCl2 in grams required is 20.82 g
Explanation:
oxidation of Nitrogen in NO2 is +4
Circulatory and respiratory
