In general: <span>(a - b)^3 = a^3 - 3 a^2b + 3 a b^2 - b<span>^3
(4x-2y)^3 = </span></span>(4x)^3 - 3 (4x)^2(2y) + 3 (4x) (2y)^2 - (2y)^3
Answer:
x - y = 118
Step-by-step explanation:
Since ∠ NOP and ∠ NOQ are complimentary then ∠ POQ = 90°
Since JOK is a straight line then
∠ JOP + ∠ POQ + ∠ QOK = 180 , that is
76 + 90 + y = 180
166 + y = 180 ( subtract 166 from both sides )
y = 14
Since MON is a straight line then
∠ MOK + ∠ KOQ + ∠ QON = 180, that is
x + 14 + 34 = 180
x + 48 = 180 ( subtract 48 from both sides )
x = 132
Thus
x - y = 132 - 14 = 118
Answer:
44
Step-by-step explanation:
Since triangles are similar, so their corresponding sides would be in proportion.
Therefore,
The solution to given system of equations are
<em><u>Solution:</u></em>
Given that we have to find solution to the system of equations
<em><u>Given equations are:</u></em>
x + 2y = 10 ------ eqn 1
y = 12x + 3 ------ eqn 2
We can solve the above equations by substitution method
<em><u>Substitute eqn 2 in eqn 1</u></em>
x + 2(12x + 3) = 10
x + 24x + 6 = 10
25x = 10 - 6
25x = 4
<em><u>Substitute the above value of x in eqn 2</u></em>
Thus the solution to given system of equations are
Answer:
w
Step-by-step explanation: