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mestny [16]
3 years ago
8

Identify the charges = Mg2+ F1

Chemistry
1 answer:
gladu [14]3 years ago
4 0

Answer:

its called drop and swap

Explanation:

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Write a balanced half-reaction for the reduction of permanganate ion mno−4 to solid manganese dioxide mno2 in acidic aqueous sol
Svetlanka [38]

The half-reaction includes either the reduction or the oxidation reaction of the redox reactions. In acidic solution permanganate ion will react with hydrogen ion to yield manganese ion and water.

<h3>What are Redox reactions?</h3>

Redox or oxidation-reduction reactions are the chemical reactions in which the oxidation and the reduction of the chemical species occur simultaneously.

Permanganate (VII) ion is a strong oxidizing agent and gets easily reduced to manganese ion in presence of the hydrogen ion in an acidic solution.

The balanced half-reaction for reduction is shown as,

\rm MnO_{4}^{-} \; (aq)+ 8H^{+} \; (aq)+ 5e^{-} \rightarrow Mn^{2+} \; (aq)+ 4H_{2}O \; (l)

Learn more about reduction reactions here:

brainly.com/question/10084275

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2 years ago
What is antimatter?Pls explain this too me<br>if you don't your dead
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Answer:

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3 years ago
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An atom has 1 proton, 2 neutrons, and 1 electrons. What is the atomic number of the atom?
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Atomic number = No. of proton = 1

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8 0
3 years ago
Nh4i(aq)+koh(aq)→ express your answer as a chemical equation. identify all of the phases in your answer.
tester [92]
NH4I (aq)  +  KOH  (aq)  in   chemical   equation  gives

   NH4I (aq)  +  KOH (aq)   =  KI  (aq)  +  H2O(l)  +  NH3  (l)

Ki  is  in  aqueous  state  H2o   is  in   liquid  state  while  NH3  is  in  liquid  state

from  the  equation  above  1 mole of  NH4I (aq) react  with  1 mole of KOH(aq) to  form  1mole of KI(aq) ,  1mole of H2O(l)  and 1  Mole  of NH3(l)
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3 years ago
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Initially, a 55.0 liter compressible container, holding 2.4 moles of a gas, exerts a pressure of 760 millimeters of mercury at a
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You would have to use the ideal gas law for this:
PV=nRT
Pressure, Volume, n=moles, R gas constant, Temperature in Kelvin
P=nRT/V
(1.8mol)(62.36)(309K)/43.0L = 805mm Hg 
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3 years ago
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