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Mariulka [41]
3 years ago
10

URGENT PLZ HELP AHHHHHHH

Chemistry
1 answer:
dexar [7]3 years ago
8 0

A, B, and D. You already answered the first one, so I wouldn't think this would be too hard

:)

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What is FeCl3+NaOH=Fe(OH)3+NaCl
nasty-shy [4]
This type of formula is use in chemistry it has  Iron ,Sodium, Hydroxyl and  Chloride unit s in the equation.
 .
3 0
3 years ago
A scientist measures out equal volumes and concentrations of hydrochloric acid and sodium hydroxide solutions. When mixed, these
olasank [31]

Answer:

Neutral solution is formed.

Explanation:

When the hydrochloric acid and sodium hydroxide which is a strong base are combined together, it produces sodium chloride which is a salt and water. This solution is known as Neutral solution because the solution do not have the characteristics or properties of either an acid or a base. If the concentration of one of the reactant is higher as compared to another reactant so the product has the characteristics of that reactant.

8 0
2 years ago
Read 2 more answers
There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In
KIM [24]

Answer:

ΔH = -470.4kJ

Explanation:

It is possible to sum 2 or more reactions to obtain the ΔH of the reaction you want to study (Hess's law). Using the reactions:

1. CaC2(s) + 2H2O(l) → C2H2(g) + Ca(OH)2(s)ΔH = −414kJ

2. 6C2H2(g) + 3CO2(g) + 4H2O(g) → 5CH2CHCO2H(g)ΔH = 132kJ

6 times the reaction 1.

6CaC2(s) + 12H2O(l) → 6C2H2(g) + 6Ca(OH)2(s)ΔH = −414kJ*6 = -2484kJ

This reaction + 2:

6CaC2(s) + 3CO2(g) + 16H2O(l) →  + 6Ca(OH)2(s) + 5CH2CHCO2H(g) ΔH = -2484kJ + 132kJ = -2352kJ

As we want to calculate the net change enthalpy in the formation of just 1 mole of acrylic acid we need to divide this last reaction in 5:

6/5CaC2(s) + 3/5CO2(g) + 16/5H2O(l) →  + 6/5Ca(OH)2(s) + CH2CHCO2H(g) ΔH = -2352kJ / 5

<h3>ΔH = -470.4kJ</h3>

4 0
2 years ago
Good chemistry question
NeX [460]
Compared to the charge and mass of a proton an electron has......

A proton has approximately the same mass as..........
5 0
3 years ago
If 56 grams of notrogen are used up by the reaction, how many grams of amonia will be produced? 1N2+3H2--&gt; 2NH3
djverab [1.8K]
1 mole of N2 produces 2 moles of NH3
OR...
14 x 2 grams of N2 produces 2(14 +3) grams of NH3
1 gram of N2 produces 34/28 grams of NH3
therefore, 56 grams produce (34/28 )x 56 =68 grams of NH3 

the answer thus would be 68 grams of NH3
5 0
3 years ago
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