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Mariulka [41]
3 years ago
10

URGENT PLZ HELP AHHHHHHH

Chemistry
1 answer:
dexar [7]3 years ago
8 0

A, B, and D. You already answered the first one, so I wouldn't think this would be too hard

:)

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A) What mass in grams of H20 is needed to react completely with 40.0 g of
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Answer:

m_{H_2O}=9.24gH_2O

Explanation:

Hello there!

In this case, since there is a 2:2 mole ratio between sodium peroxide and water according to the given reaction, it is possible to apply the following stoichiometric setup for the calculation of the required mass of water:

m_{H_2O}=40.0gNa_O_2*\frac{1molNa_O_2}{78gNa_O_2}*\frac{2molH_2O}{2molNa_O_2}  *\frac{18.02gH_2O}{1molH_2O} \\\\m_{H_2O}=9.24gH_2O

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Read 2 more answers
1. Methane (CH4) combusts as shown in the equation below. If 3 moles of methane were used in the combustion, what would be the c
umka2103 [35]

Answer:

The change in enthalpy in the combustion of 3 moles of methane = -2406 kJ

Explanation:

<u>Step 1: </u>The balanced equation

CH4(g) + 2 O2(g) → CO2(g) + 2 H2O(g)   ΔH = -802 kJ

<u>Step 2:</u> Given data

We notice that for 1 mole of methane (CH4), we need 2 moles of O2 to produce : 1 mole of CO2 and 2 moles of H20.

The enthalpy change of combustion, given here as  Δ H , tells us how much heat is either absorbed or released by the combustion of <u>one mole</u> of a substance.

In this case: we notice that the combustion of 1 mole of methane gives off (because of the negative number),  802.3 kJ  of heat.

<u>Step 3: </u>calculate the enthalpy change  for 3 moles

The -802 kj is the enthalpy change for 1 mole

The change in enthalpy for 3 moles = 3* -802 kJ = -2406 kJ

The change in enthalpy in the combustion of 3 moles of methane = -2406 kJ

5 0
3 years ago
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