Answer:
The SI base unit for amount of substance is the mole. one mole is equal to one mole potassium bromide or 119.0023 grams
Answer:
The answer to your question is: B. Nickel Sulfate
Explanation:
A. Nickel sulfur oxide this compound do not exist, this option is incorrect.
B. Nickel sulfate This compund exist and the formula is NiSO₄
C. Nickel oxygen sulfide This compound do not exist, the order of the names is inocrrect.
D. None of these This option is incorrect because because letter B is correct.
Hello!
The Sun is the main source of providing energy for the satellites. There are solar panels on the satellites to get solar energy from the sun. The sun does provide solar energy and since it's the main source of energy for the satellites, that leaves you with your answer which is solar energy.
I hope this helped!
I am, yours most sincerely,
SuperHeperThingy
Answer:
229%
Explanation:
The equation of the reaction is;
4Al(s) + 3O2(g) ----> 2Al2O3(s)
We must first determine the limiting reactant;
Number of moles of Al2O3 produced = mass/molar mass = 72.4g/101.96 g/mol = 0.71 moles
For Al
Number of moles reacted = mass/molar mass = 49.2g/27 g/mol = 1.8 moles
If 4 moles of Al yields 0.71 moles of Al2O3
1.8 moles of Al will yield 1.8 × 0.71/4 = 0.32 moles of Al2O3
For O2
Number of moles reacted = mass/molar mass = 42.6g/32g/mol = 1.33 moles
If 3 moles of O2 yields 0.71 moles of Al2O3
1.33 moles of O2 will yield 1.33 × 0.71/3 = 0.31 moles of Al2O3
Oxygen is the limiting reactant.
% yield = actual yield/ theoretical yield × 100/1
% yield = 0.71 moles/0.31 moles × 100
% yield = 229%
Answer:
9.07 L
Explanation:
<em>Calculate the volume occupied at s.t.p by 6.89 g of NH₃ gas [H = 1.0, N = 14.0].</em>
Step 1: Given and required data
- Molar mass of NH₃ (M): 17.0 g/mol
Step 2: Calculate the moles (n) of NH₃
We will use the following epxression.
n = m / M
n = 6.89 g / (17.0 g/mol) = 0.405 mol
Step 3: Calculate the volume occupied by 0.405 moles of NH₃ at STP
At STP, 1 mole of NH₃ occupies 22.4 L (assuming ideal behavior).
0.405 mol × 22.4 L/1 mol = 9.07 L
