Answer:
NO would form 65.7 g.
H₂O would form 59.13 g.
Explanation:
Given data:
Moles of NH₃ = 2.19
Moles of O₂ = 4.93
Mass of NO produced = ?
Mass of produced H₂O = ?
Solution:
First of all we will write the balance chemical equation,
4NH₃ + 5O₂ → 4NO + 6H₂O
Now we will compare the moles of NO and H₂O with ammonia from balanced chemical equation:
NH₃ : NO NH₃ : H₂O
4 : 4 4 : 6
2.19 : 2.19 2.19 : 6/4 × 2.19 = 3.285 mol
Now we will compare the moles of NO and H₂O with oxygen from balanced chemical equation:
O₂ : NO O₂ : H₂O
5 : 4 5 : 6
4.93 : 4/5×4.93 = 3.944 mol 4.93 : 6/5 × 4.93 = 5.916 mol
we can see that moles of water and nitrogen monoxide produced from the ammonia are less, so ammonia will be limiting reactant and will limit the product yield.
Mass of water = number of moles × molar mass
Mass of water = 3.285 mol × 18 g/mol
Mass of water = 59.13 g
Mass of nitrogen monoxide = number of moles × molar mass
Mass of nitrogen monoxide = 2.19 mol × 30 g/mol
Mass of nitrogen monoxide = 65.7 g
Answer:
cilia and flagella
Explanation:
In prokaryotic species , cilia are present , and in eukaryotic species , flagella is present .
Cilia and flagella both have same function , i.e. , to enable the movement of the cell , along with the movement of some substance and direct the flow of these substance along the tracts.
Cilia and flagella are composed of basal bodies.
Hence , from the given statement of the question,
The correct term is cilia and flagella .
Answer:
(Hope this helps can I pls have brainlist (crown)☺️)
Explanation:
Because the atoms in metals form a matrix through which outside electrons may easily travel, metals are good conductors of electricity and heat. They generate a sea of electrons around the positive nuclei of the interacting metal ions, rather than circling their particular atoms.
The free flow of shared electrons can carry an electric current through a metal. Carbon atoms join with iron atoms to create bonds.
Initial buret reading means the volume of acid taken in the buret and final reading means the remaining volume of acid after experiment
