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Andreas93 [3]
3 years ago
10

Convert 15.5 pounds to kilograms. Please and thank you so much!!

Chemistry
2 answers:
Elden [556K]3 years ago
8 0

Answer:

7.030682 kg

hope it helps!

AleksandrR [38]3 years ago
6 0

Answer:

7.030682

Explanation:

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Choose all true statements about the water molecule: Choose all true statements about the water molecule: Bonding between the ox
amm1812

Answer: Water is a permanent electric dipole, having permanent charge separation.

Explanation:

Hydrogen bonding is an intermolecular force having partial ionic-covalent character.

In H_2O, O is a highly electronegative atom attached to a H atom through a covalent bond. The oxygen atoms being more electronegative gets partial negative charge and H atom gets partial positive charge. Thus water is permanent electric dipole.

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4 0
3 years ago
The number 4012 has how many significant figures?​
grandymaker [24]

Answer:

8 figures.

Explanation:

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3 years ago
The pressure of an enclosed gas depends on:
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I think the correct answer from the choices listed above is the last option. The pressure of an enclosed gas depends on the number of molecules in a unit volume and their average kinetic energy, its chemical composition, the altitude about sea level and the number of atoms per molecule. Hope this helps. Have a nice day.
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4 years ago
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Which formula correctly represents the composition of iron III oxide
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6 0
3 years ago
ubstance A undergoes a first order reaction A®B with a half-life, t½, of 20 min at 25 °C. If the initial concentration of A in a
Stells [14]

Answer : The concentration of A after 80 min is, 0.100 M

Explanation :

Half-life = 20 min

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{20\text{ min}}

k=3.465\times 10^{-2}\text{ min}^{-1}

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 3.465\times 10^{-2}\text{ min}^{-1}

t = time passed by the sample  = 80 min

a = initial amount of the reactant  = 1.6 M

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

80=\frac{2.303}{3.465\times 10^{-2}}\log\frac{1.6}{a-x}

a-x=0.100M

Therefore, the concentration of A after 80 min is, 0.100 M

3 0
3 years ago
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