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Sveta_85 [38]
3 years ago
10

Suppose that prices of recently sold homes in one neighborhood have a mean of $215,000 with a standard deviation of $8900. Using

Chebyshev's Theorem, what is the minimum percentage of recently sold homes with prices between $197,200 and $232,800
Mathematics
1 answer:
bonufazy [111]3 years ago
4 0

Answer:

The minimum percentage of recently sold homes with prices between $197,200 and $232,800 is 75%.

Step-by-step explanation:

Chebyshev Theorem

The Chebyshev Theorem can also be applied to non-normal distribution. It states that:

At least 75% of the measures are within 2 standard deviations of the mean.

At least 89% of the measures are within 3 standard deviations of the mean.

An in general terms, the percentage of measures within k standard deviations of the mean is given by 100(1 - \frac{1}{k^{2}}).

In this question:

Mean of $215,000, standard deviation of $8900.

What is the minimum percentage of recently sold homes with prices between $197,200 and $232,800?

215000 - 2*8900 = 197200

215000 + 2*8900 = 232800

Within 2 standard deviations of the mean, so:

The minimum percentage of recently sold homes with prices between $197,200 and $232,800 is 75%.

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