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Sveta_85 [38]
3 years ago
10

Suppose that prices of recently sold homes in one neighborhood have a mean of $215,000 with a standard deviation of $8900. Using

Chebyshev's Theorem, what is the minimum percentage of recently sold homes with prices between $197,200 and $232,800
Mathematics
1 answer:
bonufazy [111]3 years ago
4 0

Answer:

The minimum percentage of recently sold homes with prices between $197,200 and $232,800 is 75%.

Step-by-step explanation:

Chebyshev Theorem

The Chebyshev Theorem can also be applied to non-normal distribution. It states that:

At least 75% of the measures are within 2 standard deviations of the mean.

At least 89% of the measures are within 3 standard deviations of the mean.

An in general terms, the percentage of measures within k standard deviations of the mean is given by 100(1 - \frac{1}{k^{2}}).

In this question:

Mean of $215,000, standard deviation of $8900.

What is the minimum percentage of recently sold homes with prices between $197,200 and $232,800?

215000 - 2*8900 = 197200

215000 + 2*8900 = 232800

Within 2 standard deviations of the mean, so:

The minimum percentage of recently sold homes with prices between $197,200 and $232,800 is 75%.

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Answer:

640 units squared

Step-by-step explanation:

The shape below is a trapezoid.

The formula for the  area of a trapezoid is average of the bases times the height.

The bases are the parallel lines that make up 2 of the sides of the trapezoid.

The height is the line dotted line that creates right angles and is the distance between the two bases.

The bases are 24 and 40.

To find the average, we add them together and divide by 2

(24+40)/2=64/2=32

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32*20=640

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Hope this helps!

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