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STALIN [3.7K]
3 years ago
8

Date:

Physics
1 answer:
Nikitich [7]3 years ago
4 0

Answer:

See the answer below

Explanation:

<em>Acceleration due to gravity (g) is the accelerational force experienced by a body as a result of the influence of the earth's gravitational force. It is a vector quantity, that is, it has both magnitude and direction.</em>

<em>The acceleration due to gravity is inversely proportional to the square of the radius of the earth. Hence, g at the equatorial region is slightly lesser (9.780 m/s2) than that of the polar regions (9.832 m/s2) of the earth because the earth bulges at the equator leading to a higher radius than at the poles.  </em>

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Y_Kistochka [10]

I will go to school tomorrow .....is this present tense or past tense or future tense

5 0
1 year ago
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A car accelerates along a straight road from rest to 90 km/h in 5.0 s. A) Find the magnitude of its average acceleration. B) Fin
egoroff_w [7]

Answer:

a)   A=5m/s^2

b)   V=25m/s

Explanation:

From the question we are told that:

Velocity v=90km/h=25m/s

Time t=5.0s

a)

Generally From Newton's motion equation for Average acceleration is   mathematically given by

  A=\frac{V-U}{t}

Since its from Rest Therefore

  U=0

 A=\frac{25m/s-0}{5s}

 A=5m/s^2

b)

Generally the equation for Average Velocity is mathematically given by

  V=u+at

 AT t=1.0s\\\\V=0+5(1)

 V=5m/s

 AT t=2.0s\\\\V=0+5(2)

 V=10m/s

 AT t=5.0s\\\\V=0+5(5)

 V=25m/s

 

6 0
2 years ago
You set a tuning fork into vibration at a frequency of 723 Hz and then drop it off the roof of the Physics building where the ac
zaharov [31]

Answer:

Explanation:

Given

Original Frequency f=723\ Hz

apparent Frequency f'=697\ Hz

There is change in frequency whenever source move relative to the observer.

From Doppler effect we can write as

f'=f\cdot \frac{v-v_o}{v+v_s}

where  

f'=apparent frequency  

v=velocity of sound in the given media

v_s=velocity of source

v_0=velocity of observer  

here v_0=0

697=723\cdot (\frac{343-0}{343+v_s})

v_s=(\frac{f}{f'}-1)v

v_s=(\frac{723}{697}-1)\cdot 343

v_s=12.79\approx 12.8\ m/s

i.e.fork acquired a velocity of 12.8 m/s

distance traveled by fork is given by

v^2-u^2=2as

where v=final velocity

u=initial velocity

a=acceleration

s=displacement

v_s^2-0=2\times 9.8\times s

s=\frac{12.8^2}{2\times 9.8}

s=8.35\ m

                                       

5 0
3 years ago
On a frictionless horizontal air table, puck A (with mass 0.252 kg ) is moving toward puck B (with mass 0.374 kg ), which is ini
geniusboy [140]

As we know that kinetic energy is given as

KE = \frac{1}{2}mv^2

Here we can find the initial speed of puck A by momentum conservation

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}

0.252\times v + 0 = 0.252\times (-0.115) + 0.374\times ( 0.650)

v = 0.850 m/s

now here we will have initial kinetic energy of the mass is given as

KE_i = \frac{1}{2}m_1v_1^2

KE_i = \frac{1}{2}(0.252)(0.850^2) = 0.091 J

KE_f = \frac{1}{2}(0.252)(-0.115)^2 + \frac{1}{2}(0.374)(0.650^2)

KE_f = 0.081 J

now loss of energy is given as

KE_i - KE_f = 0.091 - 0.081 = 0.010 J

6 0
3 years ago
Question 8 Unsaved
julia-pushkina [17]
The first one:
Like poles repel each other and opposite poles attract each other
3 0
3 years ago
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