Read through the paragraph on personal protective equipment on page 2 and fill in the blanks using the list of words below. Each
1 answer:
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Answer:
A) See Attachment B) See Attachment C) 186.153
Explanation:
C) Per phase Voltage= 220/∛3
= 6.037
S=V²/Z
= (6.037)²/(0.01+i0.05)
= 62051.282-i310256.41
Active power losses per phase= 62.051kW
total Active power losses= 62.051×3
=186.153kW
Answer:
Vout= 93.3V
Explanation:
For this question, consider circuit in the attachment 1.
This is the circuit of an inverting amplifier. In an inverting amplifier
Vout/Vin= -Rf/Rin
To calculate the Vout, we must find Rin and Vin. For this we must solve the input circuit (attachment 2) using Thevinine theorem. Thevnine theorem states that all voltage sources in a circuit can be replaced by an equivalent voltage source Veq and and all resistances can be replaced by an equivalent resistance Req. To find out Req all voltage sources must be short circuited (attachment 3)
1/Req= 1/R1+1/R2+1/R3
1/Req=1/6+1/3+1/3
Req=6/5
To find out Veq consider circuit in attachment 4. We will solve this circuit using nodal analysis. In nodal analysis, we use the concept that sum of currents entering a node is equal to the sum of currents leaving a node. So,
I1= I2+I3
(10-Veq)/6= (Veq-5)/3+(Veq-10)/3
Veq=8V
Now the input circuit can be simplified as shown in attachment 5. Solve for Vout using equation
Vout/Veq= -Rf/Req
Vout/8= -14/(6/5)
Vout= - 93.3
It is at an angle of 180° from Veq
