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34kurt
3 years ago
12

Which of the following types of protective equipment protects workers who are passing by from stray sparks or metal while anothe

r worker is welding?
A. Visors
B. Goggles
C. Protective Clothing
D. Dark Walls
E. Welding Screens
Engineering
1 answer:
lawyer [7]3 years ago
4 0

A protective equipment which protects workers who are passing by from stray sparks or metal while another worker is welding is: E. Welding Screens.

A wielder refers to an individual who is saddled with responsibility of joining two or more metals together by wielding.

During the process of wielding, sparks and minute metallic objects are produced, which are usually hazardous to both the wielder and other workers within the vicinity.

Hence, the following protective equipment are meant to be worn or used directly by a wielder (worker) who is wielding:

  • Visors.
  • Goggles.
  • Protective clothing.
  • Dark walls.

However, a protective equipment which protects other workers who are passing by from stray sparks or metallic objects while wielder (worker) is welding is referred to as welding screens.

Find more information: brainly.com/question/15442363

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statuscvo [17]

It is very important to know where online information comes from in order to validate, authenticate and be sure it's the right information

<h3>What are online information?</h3>

Online informations are information which are available on the internet such as search engines, social handles and other websites

In conclusion, it is very important to know where online information comes from in order to validate, authenticate and be sure it's the right information

Learn more about online information:

brainly.com/question/921157

#SPJ1

5 0
2 years ago
6. Find the heat flow in 24 hours through a refrigerator door 30.0" x 58.0" insulated with cellulose fiber 2.0" thick. The tempe
Ilia_Sergeevich [38]

Answer:

The heat flow in 24 hours through the refrigerator door is approximately 1,608.57 BTU

Explanation:

The given parameters are;

The duration of the heat transfer, t = 24 hours = 86,400 seconds

The area of the refrigerator door, A = 30.0" × 58.0" = 1,740 in.² = 1.122578 m²

The material of the insulator in the door = Cellulose fiber

The thickness of the insulator in the door, d = 2.0" = 0.0508 m

The temperature inside the fridge = 38° F = 276.4833 K

The temperature of the room = 78°F = 298.7056 K

The thermal conductivity of cellulose fiber = 0.040 W/(m·K)

By Fourier's law, the heat flow through a by conduction material is given by the following formula;

\dfrac{Q}{t} = \dfrac{k \cdot A \cdot (T_2 - T_1) }{d}

Q = \dfrac{k \cdot A \cdot (T_2 - T_1) }{d} \times t

Therefore, we have;

Q = \dfrac{0.04 \times 1.122578 \times (298.7056 - 276.4833 ) }{0.0508} \times 86,400 =1,697,131.73522

The heat flow in 24 hours through the refrigerator door, Q = 1,697,131.73522 J = 1,608.5705140685 BTU

7 0
3 years ago
Do NOT mix ____________________ with used oil. A) Transmission oilB) AntifreezeC) Hydraulic fluidsD) Synthetic oil
Scorpion4ik [409]
Do not mix Antifreeze with used oil
6 0
3 years ago
#include using namespace std; void PrintFactorial(int factCounter, int factValue){ int nextCounter; int nextValue; if (factCount
bazaltina [42]

Answer:

Check the explanation

Explanation:

Code in C++::

#include <iostream>

using namespace std;

void PrintFactorial(int factCounter, int factValue){

int nextCounter = 0;

int nextValue = 0;

if (factCounter == 0) { // Base case: 0! = 1

cout << "1" << endl;

}

else if (factCounter == 1) { // Base case: Print 1 and result

cout << factCounter << " = " << factValue << endl;

}

else { // Recursive case

cout << factCounter << " * ";

nextCounter = factCounter - 1;

nextValue = nextCounter * factValue;

/* Your solution goes here */

/**

* We just need to call the function PrintFactorial() recursively

* and pass the two parameters that are just calculated as nextCounter for factCounter

* and nextValue as factValue.

*/

PrintFactorial(nextCounter,nextValue);

}

}

int main() {

int userVal = 0;

userVal = 5;

cout << userVal << "! = ";

PrintFactorial(userVal, userVal);

return 0;

}

Output::

Test Case 1 where userVal=5::

<em><u>Attached Image 1</u></em>

Test Case 2 where userVal=6::

<em><u>Attached Image 1</u></em>

8 0
3 years ago
Storing parts outside doesn’t cause any environmental risks as long as the items are covered.
Ksivusya [100]

Answer:true

Explanation:

Jus done it

5 0
3 years ago
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