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34kurt
3 years ago
12

Which of the following types of protective equipment protects workers who are passing by from stray sparks or metal while anothe

r worker is welding?
A. Visors
B. Goggles
C. Protective Clothing
D. Dark Walls
E. Welding Screens
Engineering
1 answer:
lawyer [7]3 years ago
4 0

A protective equipment which protects workers who are passing by from stray sparks or metal while another worker is welding is: E. Welding Screens.

A wielder refers to an individual who is saddled with responsibility of joining two or more metals together by wielding.

During the process of wielding, sparks and minute metallic objects are produced, which are usually hazardous to both the wielder and other workers within the vicinity.

Hence, the following protective equipment are meant to be worn or used directly by a wielder (worker) who is wielding:

  • Visors.
  • Goggles.
  • Protective clothing.
  • Dark walls.

However, a protective equipment which protects other workers who are passing by from stray sparks or metallic objects while wielder (worker) is welding is referred to as welding screens.

Find more information: brainly.com/question/15442363

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// Radix Sort

#include<iostream>

using namespace std;

// function to get max value

int getMaximum(int array[], int n)

{

int max = array[0];

for (int i = 1; i < n; i++)

if (array[i] > max)

max = array[i];

return max;

}

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{

int mn = array[0];

for (int i = 1; i < n; i++)

if (array[i] <mn)

mn= array[i];

return mn;

}

//counting sort

void counterSort(int array[], int n, int expo)

{

int out[100]; // out max

int i, count[10] = {0};

// Store count of occurrences in count[]

for (i = 0; i < n; i++)

count[ (array[i]/expo)%10 ]++;

// Change count[i] so that count[i] now contains actual

// position of this digit in out[]

for (i = 1; i < 10; i++)

count[i] += count[i - 1];

// construct the out max

for (i = n - 1; i >= 0; i--)

{

out[count[ (array[i]/expo)%10 ] - 1] = array[i];

count[ (array[i]/expo)%10 ]--;

}

for (i = 0; i < n; i++)

array[i] = out[i];

}

void counterSortDesc(int array[], int n, int expo)

{

int out[100]; // out max

int i, count[10] = {0};

// Store count of occurrences in count[]

for (i = 0; i < n; i++)

count[ (array[i]/expo)%10 ]++;

for (i = 10; i >=1; i--)

count[i] += count[i - 1];

// construct out max

for (i = 0; i >= n-1; i++)

{

out[count[ (array[i]/expo)%10 ] - 1] = array[i];

count[ (array[i]/expo)%10 ]++;

}

// Copy the out max to array[], so that array[] now

// contains sorted numbers according to current digit

for (i = 0; i < n; i++)

array[i] = out[i];

}

// Radix Sort function

void radixsort(int array[], int n)

{

// get maximum number

int m = getMaximum(array, n);

for (int expo = 1; m/expo > 0; expo *= 10)

counterSort(array, n, expo);

}

void radixsortDesc(int array[], int n)

{

// get minimum number

int m = getMinimum(array, n);

for (int expo = 1; m/expo > 0; expo *= 10)

counterSortDesc(array, n, expo);

}

// print an max

void print(int array[], int n)

{ cout<<"\n";

for (int i = 0; i < n; i++)

cout << array[i] << " ";

}

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int main()

{

int array[] = {185, 25, 35, 90, 904, 34, 2, 66};

int n = sizeof(array)/sizeof(array[0]);

radixsort(array , n);

print(array, n);

radixsortDesc(array,n);

print(array,n);

return 0;

}

Explanation:

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