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Bond [772]
3 years ago
15

What is the function value of f 4

Mathematics
1 answer:
Schach [20]3 years ago
4 0

Answer:

0

Step-by-step explanation:

Substitute to get 4^2-8/ 4^2 equals 8, 8-8=0

hope this helps

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Randip had a balance of $86 in her checking account. She made deposits of $34 and $15. She then made withdrawals for $17 and $30
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Answer:

$88

Step-by-step explanation:

Randip's balance = initial deposit + sum of deposits - sum of withdrawals

sum of deposits = $34 + $15 = $49

sum of withdrawals =  $17 + $30 = $47

$86 + $49 - $47 = $88

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3 years ago
HELPP MEE PLZZZ<br>Subtract. y-11/4y - 5y/6y^2?
lora16 [44]
The answer is 3y-43/12y
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Triangle ABC has vertices located at A( 0, 2), B (2, 5), and C (−1, 7).
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all steps are in picture

6 0
3 years ago
obsidan is another type of igneous rock what is the density of a obsidian that has a mass of 239.2 and a volume of 92
horsena [70]
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6 0
3 years ago
10x - 5y = -25<br> l0x+8y=14
balandron [24]

Greetings,

<em>I hope you and your family are staying safe and healthy! </em>

Answer: x = -1 and y = 3

Step-by-step explanation:

10x - 5y = -25 \\10x + 8y = 14

Let's start by solving 10x - 5y = -25 for x

10x - 5y=-25

Add 5y to both sides

10x - 5y + 5y = -25+5y \\10x = 5y - 25

Now we need to divide both sides by 10

\frac{10x}{10} = \frac{5y-25}{10}

x = \frac{1}{2} y + \frac{-5}{2}

That's not the answer for x. We are not done yet :)

Now we need to substitute \frac{1}{2} y + \frac{-5}{2} for x

10x + 8y = 14\\10(\frac{1}{2} y + \frac{-5}{2} + 8y = 14

Now we need to simply both sides

13y - 25 = 14

Now we need to add 25 to both sides

13y - 25 + 25 = 14 + 25 \\13y = 39 \\y = \frac{39}{13} \\y=3

We have the valuee for y! Now we need to find the value for x

To find the value of x, we need to substitute 3 for y in:

x = \frac{1}{2} y + \frac{-5}{2} \\x = \frac{1}{2} 3 + \frac{-5}{} \\x = -1

Therefore,

The answer is x = -1 and y = 3

---------------------

Please kindly give me 5 stars and leave a thanks if you find my answer to be helpful. Thanks!

3 0
3 years ago
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