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FrozenT [24]
3 years ago
6

How is a covalent bond formed between two atoms?

Chemistry
1 answer:
Sati [7]3 years ago
5 0

Answer:

A covalent bond consists of the mutual sharing of one or more pairs of electrons between two atoms. These electrons are simultaneously attracted by the two atomic nuclei. A covalent bond forms when the difference between the electronegativities of two atoms is too small for an electron transfer to occur to form ions.

Explanation:

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In the image of the billiard table below, a cue ball is about to be struck and pushed toward the other balls
-Dominant- [34]

Answer:

c

Explanation:

6 0
3 years ago
Identify the type of interactions involved in each of the following processes taking place during the dissolution of sodium chlo
icang [17]

Answer:

A. Interactions between the ions of sodium chloride (solute-solute interactions).

B. Interactions involving dipole-dipole attractions (solvent-solvent interactions).

C. Interactions formed during hydration (solute-solvent interactions).

D. Interactions involving ion-ion attractions (solute-solute interactions).

E. Interactions associated with an exothermic process during the dissolution of sodium chloride (solute-solvent interactions).

F. Interactions between the water molecules (solvent-solvent interactions).

G. Interactions formed between the sodium ions and the oxygen atoms of water molecules (solute-solvent interactions).

Explanation:

The solution process takes place in three distinct  steps:  

  • Step 1 is the <u>separation of solvent molecules. </u>
  • Step 2 entails the <u>separation of solute molecules.</u>

These steps require energy input to break attractive intermolecular forces; therefore, <u>they are endothermic</u>.  

  • Step 3 refers to the <u>mixing of solvent and solute molecules.</u> This process can be <u>exothermic or endothermic</u>.

If the solute-solvent attraction is stronger than the solvent-solvent attraction and  solute-solute attraction, the solution process is favorable, or exothermic (ΔHsoln <  0).  If the solute-solvent interaction is weaker than the solvent-solvent and solute-solute  interactions, then the solution process is endothermic (ΔHsoln > 0).  

In the dissolution of sodium chloride, this process is exothermic.

3 0
3 years ago
Percent of water in Na2CO3 • 10H2O
Troyanec [42]
Hey there! 

In order to solve for the percentage of water in the compound, you will first need to find its total molar mass. You can do this by adding up the molar masses of each individual element in the compound. Then, you will divide the mass that you find of the water molecules by the total mass to get the percentage. 

→ Na₂CO₃ ×<span> 10 H</span>₂<span>O

</span>→ Na₂ = 22.9898 × 2 = 45.9796
→ C = 12.0107
→ O₃ = 15.999 × 3 = 47.997
→ 10 H₂O = 18.015 × 10 = 180.15

Now, just add all of those numbers up for the total molar mass. 

→ 45.9796 + 12.0107 + 47.997 + 180.15 = <span>286.1373
</span>
The last step is to divide the molar mass of the 10 water molecules by the total mass. 

→ 180.15 ÷ 286.1373 = <span>0.62959 </span>≈ 0.63

Your answer will be about 63%. 

Hope this helped you out! :-)
5 0
3 years ago
Name the compound containing only fluorine and hydrogen.
Sonbull [250]
Hydrogen has only one electron. It has one proton of nucleus and one outter electron.
7 0
3 years ago
PCL was mixed with gelatin to make a blend for elctrospun fibrous scaffold encapsulating growth factor that was admixed in the p
shusha [124]

Answer:

Explanation:

First PCL to form a scaffold, combined with gelatin.

They are made by first three forms A) made by just PCL.B) made by gelatin ratio PCL is 3:1 and last is C) made by gelatin PCL.

The decoration rate is 1%, 25% and 50% respectively.

<em>A) Growth factor is stuck in 21 days, and can not spread. In this case in vivo experiment for 7 days used highly degradable scaffold use the ability to break down due to decomposition in vivo degradation rate depends on the scaffold's acid byproduct impact.</em>

B) the amount of scaffolded degradation.

First, with scaffold A.

10 mg scaffold weight A= 1 per cent degradation.

Following degradation wt is 9.967=? Degradation per cent.

So, degradation (9.967* 1)/10= 0.9967 per cent.

Likewise for C) scaffold c 10 mg wt. Loss of 50 per cent.

After wt 8.33=? Degradation per cent.

Degradation (8.33* 50)/10=41.65 per cent.

Scaffold c degrades significantly, since the loss of wt is even greater.

7 0
4 years ago
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