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NNADVOKAT [17]
3 years ago
7

The symbol for xenon xe would be part of the noble gas notation for the element

Chemistry
2 answers:
Allushta [10]3 years ago
8 0
The symbol for xenon xe would be part of the noble gas notation for the element of radium, it is a chemical element with the symbol of Ra and the atomic number of radium is 88. It is the sixth element in group 2 of the periodic table, also known as the alkaline earth metals.<span> </span>
Mademuasel [1]3 years ago
4 0

Answer : The noble gas notation is often given to the short or abbreviated form of the electron configuration.

The use of symbol of the previous noble gas as part of the electron configuration of an element is the shortcut way to write the electron configuration.

Xenon has electron configuration as 1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 3d^{10} 4s^{2} 4p^{6} 4d^{10} 5s^{2} 5p^{6}.

Cesium has the electron configuration as 1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 3d^{10} 4s^{2} 4p^{6} 4d^{10} 5s^{2} 5p^{6} 6s^{1}

So, Cesium can be abbreviated using the symbol of xenon [Xe] 6s^{1}.

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Glucose (C6H12O6) can be fermented to yield ethanol (CH3CH2OH) and carbon dioxide (CO2). C6H12O6⟶2CH3CH2OH+2CO2 The molar mass o
jekas [21]

Answer:

The % yield is 74.45 %

Explanation:

<u>Step 1:</u> The balanced equation

C6H12O6⟶2CH3CH2OH+2CO2

<u>Step 2</u>: Data given

Molar mass glucose = 180.15 g/mol

Molar mass of ethanol = 46.08 g/mol

Molar mass of carbon dioxide = 44.01 g/mol

Mass of glucose = 61.5 grams

Mass of ethanol = 23.4 grams

<u>Step 3:</u> Calculate moles of glucose

Moles glucose = Mass glucose  / Molar mass of glucose

Moles glucose = 61.5 grams / 180.15 g/mol

Moles glucose = 0.341 moles

<u>Step 4:</u> Calculate moles of ethanol

1 mole of glucose consumed, produces 2 moles of ethanol and 2 moles of CO2

0.341 moles of glucose, will produce 2*0.341 = 0.682 moles of ethanol

<u>Step 5:</u> Calculate mass of ethanol

Mass ethanol = moles ethanol * Molar mass ethanol

Mass ethanol = 0.682 moles * 46.08 g/mol

Mass ethanol = 31.43 grams = theoretical mass

<u>Step 6:</u> Calculate % yield

% yield = actual mass / theoretical mass

% yield = (23.4 grams / 31.43 grams) * 100%

% yield = 74.45 %

The % yield is 74.45 %

7 0
3 years ago
In a 63.17 g sample of SO3, how many grams are sulfur?
Evgesh-ka [11]

Answer:

25.30 gram

Explanation:

No of moles = given mass / molar mass

No of moles = 63.17/80.06

0.7890 moles

Mass of sulphar = no of moles× molar mass of sulphar

Mass of sulphur = 0.7890×32.065

25.30 gram

4 0
3 years ago
What are the chemical formulas for..
andrezito [222]
S4O5
S3O
SeF6
N4S5
CCl9

All numbers should be subscripts
6 0
3 years ago
what are the moon phases. but be more detailed and don't put in "the phases of the moon" be more detailed.
Murrr4er [49]

Explanation:

The lunar phase or Moon phase is the shape of the Moon's directly sunlit portion as viewed from Earth. The lunar phases gradually change over a synodic month as the Moon's orbital positions around Earth and Earth around the Sun shift.

4 0
3 years ago
Read 2 more answers
A solution contains 45 grams of nitrogen gas and 40 grams of argon. What is the mole fraction of argon in this solution?
Katarina [22]
 <span>0.38 

You first calculate the total moles by dividing the grams by molecular weight: 
45 g N2 / 28.02 g/mol = 1.6 mol N2 
40 g Ar / 39.95 g/mol = 1.0 mol 

Then you divide the moles of Ar by the total number of moles: 
1.0 / (1.6 + 1.0) = 0.38 mol fraction</span>
8 0
3 years ago
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