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NNADVOKAT [17]
3 years ago
7

The symbol for xenon xe would be part of the noble gas notation for the element

Chemistry
2 answers:
Allushta [10]3 years ago
8 0
The symbol for xenon xe would be part of the noble gas notation for the element of radium, it is a chemical element with the symbol of Ra and the atomic number of radium is 88. It is the sixth element in group 2 of the periodic table, also known as the alkaline earth metals.<span> </span>
Mademuasel [1]3 years ago
4 0

Answer : The noble gas notation is often given to the short or abbreviated form of the electron configuration.

The use of symbol of the previous noble gas as part of the electron configuration of an element is the shortcut way to write the electron configuration.

Xenon has electron configuration as 1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 3d^{10} 4s^{2} 4p^{6} 4d^{10} 5s^{2} 5p^{6}.

Cesium has the electron configuration as 1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 3d^{10} 4s^{2} 4p^{6} 4d^{10} 5s^{2} 5p^{6} 6s^{1}

So, Cesium can be abbreviated using the symbol of xenon [Xe] 6s^{1}.

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1. NaOH mass of a solution of 200g in which its percentage is 25%. What mass of sulfuric acid solution is needed to completely n
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Answer:

m_{H2SO4 = 61.25 g

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m_{NaOH} = \frac{200 . 25 }{100} = 50 g

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2NaOH + H2SO4 ⇒ Na2SO4 + 2H2O

   2        :     1           :      1         :    2

 1.25                                                       (moles)

⇒  n_{H2SO4} = 1.25 × 1 ÷ 2 = 0.625 (moles) ⇒ m_{H2SO4} = 0.625 × 98 = 61.25 g

    n_{Na2SO4} = 1.25 × 1 ÷ 2 = 0.625 (moles) ⇒m_{Na2SO4} = 0.625 × 142 = 88.75 g

4 0
3 years ago
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I think option (d) is right answer

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Option (3)

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3 years ago
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