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3 years ago

What is the net ionic equation for the following reactant? Al (s) + HCl (aq) -->

Chemistry

1 answer:

rosijanka [135]3 years ago

6 0

Explanation:

hope the picture above helps u to understand:)

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How many atoms of fluorine are present in a molecule of carbon tetrafluoride CF4

Daniel [21]

There are 4, 1 Carbon 4 Fluorine

3 0

3 years ago

Determine the empirical formula. a 3.880g sample contains 0.691g of magnesium , 1.84 g of sulfur , and 1.365 g of oxygen .

Aliun [14]

Answer:

Mg S2 O3

Explanation:

.691 g of Mg is .284 mole

1.84 g of S is .5739 mole

1.365 g of O is .8531 mole you can see the ratio is ~ 1 :2 :3

Mg S2 O3

4 0

2 years ago

Which actions represent endothermic reactions? Check all that apply. an instant ice pack becoming cold, splitting a gas molecule

DerKrebs [107]

Answer is: an instant ice pack becoming cold, splitting a gas molecule and baking bread.

Endothermic reaction is chemical reaction that absorbs more energy than it releases.
In ice pack, reaction absorbs heat from the surroundings (endothermic reaction), lowering the surrounding temperature.
For splitting molecule and baking bread we must add energy to break bonds between atoms.

6 0

3 years ago

Read 2 more answers

How many moles are 21.67 L of NH4CI? Type your answer...

NNADVOKAT [17]

Answer:

0.967mole

Explanation:

Given parameters:

Volume of NH₄Cl = 21.67L

Unknown:

Number of moles = ?

Solution:

We assume that the volume was taken at standard temperature and pressure,

Then;

Number of moles = $\frac{volume }{22.4L}$

Number of moles = $\frac{21.67}{22.4}$ = 0.967mole

6 0

3 years ago

A student puts 0.020 mol of methyl methanoate into an empty and rigid 1.0 L vessel at 450 K. The pressure is measured to be 0.74

stellarik [79]

Explanation:

Starting moles of ethanol acid = 0.020 mol

At the equilibrium 50 % of the ethanol acid molecules reacted

∴ Moles of ethanol acid reacted = 0.020 mol * 50 %/100 %

= 0.010 mol

Moles of ethanol acid remain = 0.020 mol + 0.010 mol = 0.010 mol

Moles of the product $(CH3COOH)^{2}$ gas formed are calculated as

0.010 mol CH3COOH * 1 mol $(CH3COOH)^{2}$ / 2 mol CH3COOH

= 0.005 mol $(CH3COOH)^{2}$

Therefore at the equilibrium total moles of gas present in the vessel are 0.010 mol CH3COOH and 0.005 mol $(CH3COOH)^{2}$

That is total gas moles at equilibrium = 0.010 mol + 0.005 mol = 0.015 mol

Now Calculate the pressure :

0.020 mol gas has pressure of 0.74 atm therefore at the same condition what will be the pressure exerted by 0.015 mol gas

P1/n1 = P2/n2

P2 = P1*n2 / n1

= 0.74 atm * 0.015 mol / 0.020 mol

= 0.555 atm

4 0

4 years ago