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2 years ago

What is the net ionic equation for the following reactant? Al (s) + HCl (aq) -->

Chemistry

1 answer:

rosijanka [135]2 years ago

6 0

Explanation:

hope the picture above helps u to understand:)

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Neils Bohr published his model of the atomic structure in 1913. He introduced the theory of electrons traveling in orbits around

Effectus [21]

Answer:

The number of atoms in the outermost shell

Explanation:

For example, the electron shells in the alkali metals contain the following numbers of electrons:

Li: 2, 1

Na: 2, 8, 1

K: 2, 8, 8, 1

They all have one electron in their outermost shell, and they have similar chemical properties.

4 0

3 years ago

Manganese dioxide (MnO2(s), Hf = –520.0 kJ) reacts with aluminum to form aluminum oxide (AI2O3(s), Hf = –1699.8 kJ/mol) and mang

Temka [501]

Answer : The enthalpy of the reaction = -1839.6 KJ

Solution : Given,

$\Delta (H_{f})_{MnO_{2}}$ = -520.0 KJ/mole

$\Delta (H_{f})_{Al_{2}O_{3}}$ = -1699.8 KJ/mole

The balanced chemical reaction is,

$3MnO_{2}(s)+4Al(s)\rightarrow 2Al_{2}O_{3}(s)+3Mn(s)$

Formula used :

$\Delta (H_{f})_{reaction}=\sum n(\Delta H_{f})_{product}-\sum n(\Delta H_{f})_{reactant}$

$\Delta (H_{f})_{reaction}=(2\times \Delta H_{Al_{2}O_{3}(s)}+3\times \Delta H_{Mn(s)} )-(3\times \Delta H_{MnO_{2}(s) }+4\times\Delta H_{Al}(s))$

We know that the standard enthalpy of formation of the element is equal to Zero.

Therefore, the enthalpy of formation of (Mn) and (Al) is equal to zero.

Now, put all the values in above formula, we get

$\Delta (H_{f})_{reaction}=[2moles\times (-1699.8 KJ/mole)}+3moles\times (0\text{ KJ/mole}})]-[(3moles\times(-520.0KJ/mole }+4moles\times(0\text{ KJ/mole})]$

= (-3399.6) + (1560)

= -1839.6 KJ

5 0

3 years ago

What is the reaction quotient, Q, for this system when [N2] = 2.00 M, [H2] = 2.00 M, and [NH3] = 1.00 M at 472°C?

cupoosta [38]

Answer : The value of reaction quotient, Q is 0.0625.

Solution : Given,

Concentration of $N_2$ = 2.00 M

Concentration of $H_2$ = 2.00 M

Concentration of $NH_3$ = 1.00 M

Reaction quotient : It is defined as a concentration of a chemical species involved in the chemical reaction.

The balanced equilibrium reaction is,

$N_2+3H_2\rightleftharpoons 2NH_3$

The expression of reaction quotient for this reaction is,

$Q=\frac{[Product]^p}{[Reactant]^r}\\Q=\frac{[NH_3]^2}{[N_2]^1[H_2]^3}$

Now put all the given values in this expression, we get

$Q=\frac{(1.00)^2}{(2.00)^1(2.00)^3}=0.0625$

Therefore, the value of reaction quotient, Q is 0.0625.

3 0

3 years ago

Please help me no links <br> if good answer you get brainliest

Olin [163]

The crystals will not be oxidised since it will be underground

5 0

2 years ago

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Assume you mixed 5 µl of your cod fish homogenate with 195 µl working solution. The fluorometer displays a measurement of 12.2 µ

11111nata11111 [884]

Answer:

Hallo

Explanation:

I took that question

3 0

3 years ago