2503(g) → 2502(g) O2(g)

The theoretical yield of NaBr from

Dvinal [7]

the percent yield of the reaction is 100%.

The percent yield is calculated as the experimental yield divided by the theoretical yield x 100%:

% yield = actual yield / theoretical yield * 100%

% yield of a reaction in this case Rate

In this case, the molar mass of NaBr is 102.9 g / mol, as you know:

444 actual yield = 7.08 mol x 102.9 g / mol = 728.532 g

theoretical yield = 7.08 mol x 102.9 g / mol = 728.532 g

, Replaced by the definition of percent yield:

percent yield = 728.532 grams / 728.532 grams * 100%

percent yield = 100%

Finally, the percent yield of the reaction is 100%.

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FeBr3 is iron bromide. Also known as iron bromide. Iron bromide is an ionic compound in which iron is in a +3 oxidation state.

Learn more about % yield here:brainly.com/question/27979178

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5 0

2 years ago

To see a RED object, all the light is absorbed except the Red and that is what we see as the color True False

Dafna11 [192]

Answer: True

Explanation:

Let's begin by explaining that the vision phenomenon depends on three elements: the observer, the object and the light source.

In addition, objects have pigments, which generally absorb more light than they reflect (they absorb certain wavelengths and reflect others). Therefore, the color that a given object seems to have depends on which parts of the visible electromagnetic spectrum are reflected and which parts are absorbed.

In this sense, the colours we see are in fact the wavelengths that are reflected or transmitted from the object. For example, a red object has that color because when it is illuminated whith white light, the pigments on this object abrsorb all the the wavelengths of the visible electromagnetic spectrum, except red. That is why red light is the only light that is reflected from the mentioned object.

7 0

3 years ago

Classify each change as physical or chemical.

trasher [3.6K]

A chemical

B physical

C physical

D Chemical

4 0

3 years ago

HELP ASAP PLZ!!!! Find the mass of each substance. Show your work.

Gemiola [76]

Answer:

A. m C5H12 = 108.23 g

B. m F2 = 547.142 g

C. m Ca(CN)2 = 71.85 g

Explanation:

mass (m) = mol (n) × molecular weigth (Mw)

∴ Mw C5H12 = ((12.011)(5)) + ((1.008)(12)) = 72.151 g/mol C5H12

∴ Mw F2 = (18.998)(2) = 37.996 g/mol F2

∴ Mw = Ca(CN)2 = 40.078+((12.011+14.007)(2)) = 92.114 g/mol Ca(CN)2

A. m C5H12 = ( 1.50 mol)×(72.151 g/mol) = 108.23 g C5H12

B. m F2 = (14.4 mol)×(37.996 g/mol) = 547.142 g F2

C. m Ca(CN)2 = (0.780 mol)×(92.114 g/mol) = 71.85 g Ca(CN)2

8 0

3 years ago

Nitric oxide, NO, is made from the oxidation of NH3, and the reaction is represented by the equation: 4NH3 + 5O2 → 4NO + 6H2O Wh

tamaranim1 [39]

Answer:

16.16g of O2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

4NH3 + 5O2 → 4NO + 6H2O

Next, we shall determine the mass of NH3 and O2 that reacted from the balanced equation. This is illustrated below:

Molar mass of NH3 = 14 + (3x1) = 17g/mol

Mass of NH3 from the balanced equation = 4 x 17 = 68g

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 from the balanced equation = 5 x 32 = 160g.

From the balanced equation above,

68g of NH3 reacted with 160g of O2.

Now, we can calculate the mass of O2 that will be required to react completely with 6.87 g of NH3. This is illustrated below:

From the balanced equation above,

68g of NH3 reacted with 160g of O2

Therefore, 6.87g of NH3 will react with = (6.87 x 160)/68 = 16.16g of O2.

Therefore, 16.16g of O2 is needed for the reaction.

4 0

3 years ago