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s2008m [1.1K]
3 years ago
10

Plz helpppp

Chemistry
2 answers:
Vlada [557]3 years ago
4 0

Answer:

Water

Water

Explanation:

GenaCL600 [577]3 years ago
4 0

Answer:

1 Water 2 wind

Explanation:

is the answer

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What is the mass in grams for a piece of lead that has a volume of 14.8 cubic centimeters? The density of lead is 11.4 g/cc.
Oksi-84 [34.3K]

Answer:

168.72 grams

Explanation:

Density = Mass/Volume

Volume = 14.8

Mass = ?

Density = 11.4

Let x = mass

11.4 = x/14.8

Multiply both sides by 14.8

14.8(11.4 = x/14.8)

x = 168.72

8 0
3 years ago
Why is coal non renewable
sweet-ann [11.9K]

Answer:

Coal is classified as a nonrenewable energy source because it takes millions of years to form. Coal contains the energy stored by plants that lived hundreds of millions of years ago in swampy forests.

8 0
3 years ago
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Calculate the molarity of a solution prepared by dissolving 6.80 grams of AgNO3 in 2.50 liters of solution.
tester [92]

Answer:

0.016M

Explanation:

First we find the mole of AgNO3 by using the formula mass/molar mass..

Then we find molarity by the formula mole/volume...

I hope you get this..

7 0
3 years ago
If one pound is the same as 454 grams, then convert the mass of 78 grams to pounds.
LiRa [457]

Answer:

0.17 lb

Explanation:

78 g * (1 lb/454 g)=0.17 lb

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4 0
3 years ago
Determine the mole fractions and partial pressures of CO2, CH4, and He in a sample of gas that contains 1.20 moles of CO2, 1.79
BARSIC [14]

Answer :  The mole fraction and partial pressure of CH_4,CO_2 and He gases are, 0.267, 0.179, 0.554 and 1.54, 1.03 and 3.20 atm respectively.

Explanation : Given,

Moles of CH_4 = 1.79 mole

Moles of CO_2 = 1.20 mole

Moles of He = 3.71 mole

Now we have to calculate the mole fraction of CH_4,CO_2 and He gases.

\text{Mole fraction of }CH_4=\frac{\text{Moles of }CH_4}{\text{Moles of }CH_4+\text{Moles of }CO_2+\text{Moles of }He}

\text{Mole fraction of }CH_4=\frac{1.79}{1.79+1.20+3.71}=0.267

and,

\text{Mole fraction of }CO_2=\frac{\text{Moles of }CO_2}{\text{Moles of }CH_4+\text{Moles of }CO_2+\text{Moles of }He}

\text{Mole fraction of }CO_2=\frac{1.20}{1.79+1.20+3.71}=0.179

and,

\text{Mole fraction of }He=\frac{\text{Moles of }He}{\text{Moles of }CH_4+\text{Moles of }CO_2+\text{Moles of }He}

\text{Mole fraction of }He=\frac{3.71}{1.79+1.20+3.71}=0.554

Thus, the mole fraction of CH_4,CO_2 and He gases are, 0.267, 0.179 and 0.554 respectively.

Now we have to calculate the partial pressure of CH_4,CO_2 and He gases.

According to the Raoult's law,

p_i=X_i\times p_T

where,

p_i = partial pressure of gas

p_T = total pressure of gas  = 5.78 atm

X_i = mole fraction of gas

p_{CH_4}=X_{CH_4}\times p_T

p_{CH_4}=0.267\times 5.78atm=1.54atm

and,

p_{CO_2}=X_{CO_2}\times p_T

p_{CO_2}=0.179\times 5.78atm=1.03atm

and,

p_{He}=X_{He}\times p_T

p_{He}=0.554\times 5.78atm=3.20atm

Thus, the partial pressure of CH_4,CO_2 and He gases are, 1.54, 1.03 and 3.20 atm respectively.

4 0
3 years ago
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