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nikdorinn [45]
3 years ago
11

4. What is the volume of a 25% methyl solution that contains 20mL of methyl?

Chemistry
2 answers:
Akimi4 [234]3 years ago
4 0
25% of 20
%=100
25/100 x 20
1/4 x 20
The answer is equal to 5
quester [9]3 years ago
3 0

Answer:

A.) 6.25 mL

Explanation:

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Complete this equation for the dissociation of na2co3(aq). omit water from the equation because it is understood to be present.
Savatey [412]
Net overall dissociation:
Na2CO3 ---> 2Na(-) + CO3(2-)

*The ion charge is in parenthesis
6 0
3 years ago
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One atomic model describes electrons moving in clouds around the nucleus.
bixtya [17]

Answer: D.  It is the currently accepted atomic model.

Explanation:

It is the mordern atomic model, also known as the Electron Cloud Model. Indicating that the nucleus of an atom is surrounded by a cloud of electrons.

8 0
3 years ago
Calculate the percent by volume of a solution that has 75 mL of solute dissolved in 375 mL of solution. Show your work and round
Mandarinka [93]

Answer:

The answer is 20 % V/V

Explanation:

We use this formula for calculate the %V/V:

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<em>The% V / V represents the amount of ml of solute dissolved in 100 ml of solution</em>

7 0
4 years ago
Potassium cyanide is a toxic substance, and the median lethal dose depends on the mass of the person or animal that ingests it.
Artemon [7]

Answer:

88,7 mL of solution

Explanation:

Molarity (Represented as M) is an unit of chemical concentration that is defined as the ratio between moles of solute per liters of solution, that is:

Molarity = moles of solute / Liters of solution

If molarity of KCN solution is 0,0820M and moles of KCN are 7,27x10⁻³ moles:

0,0820M = 7,27x10⁻³ moles / Liters of solution

Liters of solution = 0,0887L = <em>88,7 mL of solution</em>

I hope it helps!

4 0
3 years ago
How much carbon would be needed to make 8.8g of carbon dioxide?<br>​
PIT_PIT [208]
The calculation for such a question can be achieved via Avogadro hypothesis

We know molar mass of CO2 is 44g/mole which is the sum of atomic masses i.e; C and 2 oxygen atoms

Molar mass of CO2 =12(C)+2*16(O) = 44 g/mole will contain 6.023 ※10^23 CO2 molecules ..

44g/mole = 6.023 ※10^23 CO2 molecules

=> 1g = (6.023/44) ※10^23 CO2 molecules

==> 8.80g = 8.80(6.023÷44)10^23 = 1.2046 ※10^23 molecules of CO2….

Thus there r 1.2046 ※10^23 molecules of CO2 in 8.80g

if u need to calculate no. of carbon atoms then multiply result by 1 and if u need no of oxygen atoms in 8.80g of co2 then multiply the result by 2 ….
7 0
2 years ago
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