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LekaFEV [45]
2 years ago
8

Effects of heat on matter​

Physics
1 answer:
kumpel [21]2 years ago
3 0

Answer:

it can melt orcan put them past their boiling point

Explanation:

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Hi Friends!<br><br>please help me with these questions!<br><br>SUBJECT: Chemistry, Physics,Biology
satela [25.4K]

Answer:

q.1 : Air near candle gets heated up and after this it rises by convection so the thermometer B will receive more heat than the thermometer A So, according to the given condition thermometer B will show a greater rise in temperature.

q.2 : x is the pure sample of compound . y is the pure sample of element . z is the mixture of different elements

q.3 : the saliva contains an enzyme salivary amylase (ptyalin) which converts starch in roti into maltose, isomaltose and small dextrins called a-dextrin.

6 0
3 years ago
A special triangular frame is being made for a piece of artwork. The the base of the triangular frame must be 90 cm. If the area
Mashutka [201]

Answer:

Explanation:

base of triangular frame, b = 90 cm

Area, A = 765 cm²

Let the height is h.

Area of a triangular frame = 1/2 x base x height

765 = 0.5 x 90 x h

h = 17 cm

Thus, the height of triangular frame is 17 cm.

5 0
3 years ago
Which statement best describes the relationship between an object's density and its index of refraction? as the optical density
babunello [35]
For future references, the answer is B.
4 0
3 years ago
Read 2 more answers
The total potential and kinetic energy of all the microscopic particles in an object make up its
Gala2k [10]
It makes up B. thermal energy
8 0
3 years ago
Part A If the velocity of a pitched ball has a magnitude of 47.5 m/s and the batted ball's velocity is 51.5 m/s in the opposite
nalin [4]

Explanation:

Let us assume that the mass of a pitched ball is 0.145 kg.

Initial velocity of the pitched ball, u = 47.5 m/s

Final speed of the ball, v = -51.5 m/s (in opposite direction)

We need to find the magnitude of the change in momentum of the ball and the impulse applied to it by the bat. The change in momentum of the ball is given by :

\Delta p=m(v-u)\\\\\Delta p=0.145\times ((-51.5)-47.5)\\\\\Delta p=-14.355\ kg-m/s

So, the magnitude of the change in momentum of the ball is 14.355 kg-m/s.

Let the the ball remains in contact with the bat for 2.00 ms. The impulse is given by :

J=\dfrac{\Delta p}{t}\\\\J=\dfrac{14.355}{2\times 10^{-3}}\\\\J=7177.5\ kg-m/s

Hence, this is the required solution.

7 0
3 years ago
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