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3 years ago

7

If you put a straw into a glass of water, the straw looks to be bent, although nothing has really happened to the straw. The ter

m that describes this property of light is

1 answer:

almond37 [142]3 years ago

4 0

The property of light describing this scenario is refraction.

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A disk of mass M and radius R rotates at angular velocity ω0. Another disk of mass M and radius r is dropped on top of the rotat

AleksandrR [38]

Answer:

$\omega = \frac{(R^2\omega_o}{(R^2 + r^2)}$

Explanation:

As we know that there is no external torque on the system of two disc

then the angular momentum of the system will remains conserved

So we will have

$L_i = L_f$

now we have

$L_i = (\frac{1}{2}MR^2)\omega_o$

also we have

$L_f = (\frac{1}{2}MR^2 + \frac{1}{2}Mr^2)\omega$

now from above equation we have

$(\frac{1}{2}MR^2)\omega_o = (\frac{1}{2}MR^2 + \frac{1}{2}Mr^2)\omega$

now we have

$\omega = \frac{MR^2\omega_o}{(MR^2 + Mr^2)}$

$\omega = \frac{(R^2\omega_o}{(R^2 + r^2)}$

6 0

3 years ago

Two long, parallel wires separated by 2.00 cm carry currents in opposite directions. The current in one wire is 1.75 A, and the

Natasha_Volkova [10]

The force per unit length between the two wires is $6.0\cdot 10^{-5} N/m$

Explanation:

The magnitude of the force per unit length exerted between two current-carrying wires is given by

$\frac{F}{L}=\frac{\mu_0 I_1 I_2}{2\pi r}$

where

$\mu_0 = 4\pi \cdot 10^{-7} Tm/A$ is the vacuum permeability

$I_1, I_2$ are the currents in the two wires

r is the separation between the two wires

For the wires in this problem, we have

$I_1 = 1.75 A$

$I_2 = 3.45 A$

r = 2.00 cm = 0.02 m

Substituting into the equation, we find

$\frac{F}{L}=\frac{(4\pi \cdot 10^{-7})(1.75)(3.45)}{2\pi (0.02)}=6.0\cdot 10^{-5} N/m$

Learn more about current and magnetic fields:

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#LearnwithBrainly

4 0

3 years ago

65 POINTS! PLEASE ANSWER EVERY QUESTION! NEED HELP ASAP!

otez555 [7]

Maybe you can split up the questions. I will try to answer your first question.

1. In an elastic collision, momentum is conserved. The momentum before the collision is equal to the momentum after the collision. This is a consequence of Newton's 3rd law. (Action = Reaction)

2. Momentum: p = m₁v₁ + m₂v₂

m₁ mass of ball A
v₁ velocity of ball A
m₂ mass of ball B
v₂ velocity of ball B

Momentum before the collision:
p = 2*9 + 3*(-6) = 18 - 18 = 0

Momentum after the collision:
p = 2*(-9) + 3*6 = -18 + 18 = 0

3: mv + m(-v) = m(-v) + m(v)
the velocities would reverse.

4.This question is not factual since the energy of an elastic collision must also be conserved. The final velocities should be: v₁ = -1 m/s and v₂ = 5 m/s. That said assuming the given velocities were correct:
before collision
p = 10*3 + 5*(-3) = 30 - 15 = 15
after collision:
p = 10*(-2) + 5 * v₂ = 15
v₂ = 7

5.You figure out.

3 0

3 years ago

Why do elements in the same group or column of the periodic table have similar properties? A. They have the same number of proto

Oxana [17]

The Answer is C. The outer shell electrons are the electrons which are involved with chemical reactions and bonding. All elements in the same group have different number of total electrons but ALL have the same number of outer shell electrons. This is why they exhibit similar chemical properties.

3 0

4 years ago

A man attempts to pick up his suitcase of weight ws by pulling straight up on the handle. (See Figure 1) However, he is unable t

cupoosta [38]

Answer:

Normal force, $N = W_s - F$

Explanation:

Let $w_s$ is the weight of suitcase. A man attempts to pick up his suitcase by pulling straight up on the handle. The weight of the suitcase in downward direction. The normal force is acting in upward direction. Let F is the force with which it is pulled straight up.

So, the normal force is given by :

$N = W_s - F$

N = mg - F

mg is the weight of the suitcase.

Hence, this is the required solution.

3 0

4 years ago