The speed of car is 106.67 miles per hour
To solve problems involving speed and distance we are required to first find speed or distance travelled in an hourly timeframe
It is given that car takes 4 hours to cover the distance at a speed of 40 miles per hour
Therefore, total distance travelled by the car= speed x time
= 40 miles per hour x 4 hour
=160 miles
We are required to find the speed of the car if the distance is to be covered in 1.5 hours
We are required to find the speed by the formula speed= Distance/time
distance= 160 miles time = 1.5 hour
speed= 160/1.5=106.666=106.67 miles per hour
Hence the speed is 106.67 miles per hour
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It will read the temperature of the atmosphere.It is unable to read the temperature of the sun because some of the heat energy from the sun is absorbed by the layer of air molecules on Earth.
Answer:
The compression is
.
Explanation:
A Hooke's law spring compressed has a potential energy

where k is the spring constant and
the distance to the equilibrium position.
A mass m moving at speed v has a kinetic energy
.
So, in the first part of the problem, the spring is compressed a distance d, and then launch the mass at velocity
. Knowing that the energy is constant.

If we want to double the kinetic energy, then, the knew kinetic energy for a obtained by compressing the spring a distance D, implies:

But, in the left side we can use the previous equation to obtain:





And this is the compression we are looking for
Answer:

Explanation:
Using Kepler's third law, we can relate the orbital periods of the planets and their average distances from the Sun, as follows:

Where
and
are the orbital periods of Mercury and Earth respectively. We have
and
. Replacing this and solving for

Answer:
8.756 rad/s²
Explanation:
Given that:
A motorcycle accelerates uniformly from rest, then initial velocity v_i = 0 m/s
It final velocity v_f = 24.8 m/s
time (t) = 9.87 s
radius (r) of each tire = 0.287 m
Firstly; the linear acceleration of the motor cycle is determined as follows:
=(V_f - v_i)/t
=(24.8-0)/9.87
=2.513 m/s²
Then; the magnitude of angular acceleration
α =
/r
=2.513/0.287
=8.756 rad/s²