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MariettaO [177]
3 years ago
7

A community calendar allows nonprofit organizations to add events and their intended purposes for community members to see.

Physics
1 answer:
lbvjy [14]3 years ago
8 0

Out of all given choices, activities and donor list can be found on the given kind of informative website.

Answer: Option A and B

<u>Explanation:</u>

Non-profit need to do the examination and for sake activities that simply aren't successful. And afterwards, they have to look to a portion of these auxiliary changes that to discover increasingly productive approaches to make a feasible money related model for their social change work.

When occasions are crucial, allowed to visit, and concentrated on developing as well as managing present or potential significant donors (people, establishments, corporate pioneers, they can bode well. Yet, only in the event that you catch up with participants on a one-on-one premise to additionally put them in the association and in the long run request that they contribute or reestablish their commitments.

On the off chance, you don't charge those to visit with the goal that can approach them for a greater, and progressively important blessing not far off.

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Equation: S=D]
Ahat [919]

The speed of car is 106.67 miles per hour

To solve problems involving speed and distance we are required to first find speed or distance travelled in an hourly timeframe

It is given that car takes 4 hours to cover the distance at a speed of 40 miles per hour

Therefore, total distance travelled by the car= speed x time

                                                                          = 40 miles per hour x 4 hour

                                                                          =160 miles

We are required to find the speed of the car if the distance is to be covered in 1.5 hours

We are required to find the speed by the formula speed= Distance/time

distance= 160 miles     time = 1.5 hour

speed= 160/1.5=106.666=106.67 miles per hour

Hence the speed is 106.67 miles per hour

For further reference:

brainly.com/question/10930186?referrer=searchResults

#SPJ9

7 0
2 years ago
A thermometer is placed directly sunlight will it read the temperature of the air or of the sun or of something else??
Norma-Jean [14]
It will read the temperature of the atmosphere.It is unable to read the temperature of the sun because some of the heat energy from the sun is absorbed by the layer of air molecules on Earth.
7 0
3 years ago
A Hooke's law spring is mounted horizontally over a frictionless surface. The spring is then compressed a distance d and is used
zloy xaker [14]

Answer:

The compression is \sqrt{2} \  d.

Explanation:

A Hooke's law spring compressed has a potential energy

E_{potential} = \frac{1}{2} k (\Delta x)^2

where k is the spring constant and \Delta x the distance to the equilibrium position.

A mass m moving at speed v has a kinetic energy

E_{kinetic} = \frac{1}{2} m v^2.

So, in the first part of the problem, the spring is compressed a distance d, and then launch the mass at velocity v_1. Knowing that the energy is constant.

\frac{1}{2} m v_1^2 = \frac{1}{2} k d^2

If we want to double the kinetic energy, then, the knew kinetic energy for a obtained by compressing the spring a distance D, implies:

2 * (\frac{1}{2} m v_1^2) = \frac{1}{2} k D^2

But, in the left side we can use the previous equation to obtain:

2 * (\frac{1}{2} k d^2) = \frac{1}{2} k D^2

D^2 =  \frac{2 \ (\frac{1}{2} k d^2)}{\frac{1}{2} k}

D^2 =  2 \  d^2

D =  \sqrt{2 \  d^2}

D =  \sqrt{2} \  d

And this is the compression we are looking for

3 0
4 years ago
Read 2 more answers
The average distance of the planet mercury from the sun is 0.39 times the average distance of the earth from the sun. How long i
Stels [109]

Answer:

T_1=0.24y

Explanation:

Using Kepler's third law, we can relate the orbital periods of the planets and their average distances from the Sun, as follows:

(\frac{T_1}{T_2})^2=(\frac{D_1}{D_2})^3

Where T_1 and T_2 are the orbital periods of Mercury and Earth respectively. We have D_1=0.39D_2 and T_2=1y. Replacing this and solving for

T_1^2=T_2^2(\frac{D_1}{D_2})^3\\T_1^2=(1y)^2(\frac{0.39D_2}{D_2})^3\\T_1^2=1y^2(0.39)^3\\T_1^2=0.059319y^2\\T_1=0.24y

5 0
3 years ago
A motorcycle accelerates uniformly from rest and reaches a linear speed of 24.8 m/s in a time of 9.87 s. The radius of each tire
Vinvika [58]

Answer:

8.756 rad/s²

Explanation:

Given that:

A motorcycle accelerates uniformly from rest, then initial velocity v_i = 0 m/s

It final velocity v_f = 24.8 m/s

time (t) = 9.87 s

radius (r) of each tire  = 0.287 m

Firstly; the linear acceleration of the motor cycle  is determined as follows:

a_T =(V_f - v_i)/t

=(24.8-0)/9.87

=2.513 m/s²

Then;  the magnitude of angular acceleration

α =a_T /r

=2.513/0.287

=8.756 rad/s²

6 0
4 years ago
Read 2 more answers
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