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Arada [10]
3 years ago
14

In a factory, where would you expect to find the manager?

Biology
2 answers:
Maru [420]3 years ago
5 0

Answer: In the control room!

Explanation:

laila [671]3 years ago
5 0

Answer:

By my calculations, there are 280 defects in the unit order.

Explanation:

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Which increase the rate of soil formation? Check all that apply. A. mixed layers B. large grain sizes C. more precipitation D. w
Feliz [49]

The answers are

B. large grain sizes C. more precipitation D. warmer temperatures

4 0
3 years ago
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What molecule do plants pull from the air that is used to make sugar?
Mrac [35]

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carbon dioxide

Explanation:

its yummy for the tummy

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Does the process of DNA replication result in a copy of the original DNA molecule?
RUDIKE [14]

Answer:

it results in 2 exact copies of the original dna strand

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The dna is unzipped and the two strands are used as templates for the 2 new dna molecules

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If more snakes moved into this environment, then
alexandr402 [8]

Answer:

B. <em>The number of grasshopers would go up.</em>

Explanation:

A. is incorrect because it would decrease

C is incorrect  because it would also decrease

D is incorrect because snakes dont eat Hawks, but Hawks eat them

B is <em>correct</em> because since snakes would eat the toads, there would be no toads eating grasshoppers

Hope this helps!!!

4 0
2 years ago
HELP ASAP I WILL GIVE BRAINLIST
adelina 88 [10]

Answer:

1) CO₂

2) 0.2551 g

Explanation:

The balanced reactions are:

CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂

MgCO₃ + 2HCl → MgCl₂ + H₂O + CO₂

1) The gas produced is CO₂.

2) Calculate mass of CaCO₃:

(0.5236 g) (0.4230) = 0.2215 g CaCO₃

Convert to moles:

(0.2215 g CaCO₃) (1 mol / 100.1 g) = 0.002213 mol CaCO₃

Find moles of CaCO₃:

(0.002213 mol CaCO₃) (1 mol CO₂ / mol CaCO₃) = 0.002213 mol CO₂

Convert to mass:

(0.002213 mol CO₂) (44.01 g / mol) = 0.09738 g CO₂

Calculate mass of MgCO₃:

(0.5236 g) (0.5770) = 0.3021 g MgCO₃

Convert to moles:

(0.3021 g MgCO₃) (1 mol / 84.31 g) = 0.003583 mol MgCO₃

Find moles of MgCO₃:

(0.003583 mol MgCO₃) (1 mol CO₂ / mol MgCO₃) = 0.003583 mol CO₂

Convert to mass:

(0.003583 mol CO₂) (44.01 g / mol) = 0.1577 g CO₂

Total mass of CO₂:

0.09738 g CO₂ + 0.1577 g CO₂ = 0.2551 g CO₂

8 0
3 years ago
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