Answer:
28
Step-by-step explanation:
Answer:
All of the above
Step-by-step explanation:
dy/dt = y/3 (18 − y)
0 = y/3 (18 − y)
y = 0 or 18
d²y/dt² = y/3 (-dy/dt) + (1/3 dy/dt) (18 − y)
d²y/dt² = dy/dt (-y/3 + 6 − y/3)
d²y/dt² = dy/dt (6 − 2y/3)
d²y/dt² = y/3 (18 − y) (6 − 2y/3)
0 = y/3 (18 − y) (6 − 2y/3)
y = 0, 9, 18
y" = 0 at y = 9 and changes signs from + to -, so y' is a maximum at y = 9.
y' and y" = 0 at y = 0 and y = 18, so those are both asymptotes / limiting values.
Answer:
B) 10 visits
Step-by-step explanation:
Let the number of visits be x.
Pool A cost: 1x + 40 = x + 40
Pool B cost: 5x
Set the two costs equal and solve for x.
x + 40 = 5x
Subtract 5x from both sides. Subtract 40 from both sides.
-4x = -40
Divide both sides by -4.
x = 10
Answer: B) 10 visits
(5,36)(8,48)
slope = (48 - 36) / (8 - 5) = 12/3 = 4
y = mx + b
slope(m) = 4
(5,36)...x = 5 and y = 36
now sub and find b
36 = 4(5) + b
36 = 20 + b
36 - 20 = b
16 = b
equation is : y = 4x + 16.....in standard form : 4x - y = -16 <==
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function notation : f(x) = 4x + 16
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x axis will be ur hrs....I would label them at intervals of 1
y axis will be total cost of renting the bike......as far as the intervals...not sure how to label them.....sorry....I wanna say intervals of 2...but am not sure
y = 4x + 16
slope = 4
y int = (0,16)
x int = (-4,0)
so start at (-4,0)....and since ur slope is 4, go up 4 and to the right 1...keep doing this and u will cross the y axis at (0,16)
