Answer:
C5 and its absolute configuration is R
Explanation:
<u>A chiral center is a carbon atom (C) which is bonded to four different groups, generating optical activity in the molecule. </u>
The first two chiral centers are:
- C1: bonded to OH, H, the carbon chain (seen from left to right) and the carbon chain (seen fron rigth to left).
- C2: bonded to CH3, the above C and its CH3, the carbon chain (seen from left to right) and the carbon chain (seen fron rigth to left).
The thrid chiral center is C5, which is bonded to H, the above C and its CH3, the carbon chain (seen from left to right) and the carbon chain (seen fron rigth to left).
The absolute configuration of it is R (clockwise)
Answer:
A
Explanation:
Halogens have 7 electrons in their valence shell and requires just one electron to achieve their stable structure. Because of this they have high electron affinity and hence high electronegativity and they are strong oxidizing agents. Oxidation is the loss of electrons . Halogens have a high readiness to take electrons which a metal loses thereby oxidizing it. The other options are wrong as they involve compounds and not the elemental form as stated in the question.
For this problem, we use the formula for
radioactive decay which is expressed as follows:<span>
An = Aoe^-kt
where An is the amount left after time t, Ao is
the initial amount and k is a constant.
We calculate as follows:
An = Aoe^-kt
0.5 = e^-k(4.5)
k = 0.1540
An = Aoe^-kt
An = 16e^-0.1540(18)
<span>An = 1.00 mg</span></span>
Hope this answers the question. Have a nice day.
The correct equilibrium expression would be one that has products over reactants, and to the power of their stoichiometric coefficient. Also, it would not include any liquids or solids.
The equilibrium expression for your balanced reaction is:
Answer:
The mass is 20, 89 grams of He.
Explanation:
We calculate the weight of 1 mol of He, from the atomic weight of each element obtained from the periodic table: Weight 1 mol He= 4, 0020602 g. 1 mol He-----4, 0020602 g. 5,22 mol He---x= (5,22 mol He x4, 0020602 g)/ 1 mol He= 20, 89 g
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