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oksano4ka [1.4K]
3 years ago
9

Why do scientist need government fundings?

Chemistry
2 answers:
Veseljchak [2.6K]3 years ago
8 0

Becuase they need special equipment and things like that that may not be available in the state i think

oksano4ka [1.4K]3 years ago
6 0
They need special equipment
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If a reaction occurs, what will be the products of the unbalanced reaction below?Zn(s) + HCl(aq) -->
irakobra [83]

The products will be ZnCl_2(s) + H_2(g)

<h3>Chemical reactions</h3>

Zn is higher than hydrogen in the reactivity series. Thus, it will be able to displace hydrogen from the acid.

The equation of the reaction becomes: Zn(s) + HCl(aq) -- > ZnCl_2 (s) + H_2 (g)

Hydrogen gas is released as a result. In fact, it is one of the ways of preparing hydrogen gas in the laboratory.

More on chemical reactivity can be found here: brainly.com/question/9621716

#SPJ1

3 0
2 years ago
Morgan wants to compare the weather conditions at her school each day during the week. She decides to measure and record weather
Firlakuza [10]

Answer: Air Temperature

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3 years ago
The activation energy of an uncatalyzed reaction is 95kJ/mol. The addition of a catalyst lowers the activation energy to 55kJ/mo
notka56 [123]

Answer:

a) at 25°C the rate of reaction increases by a factor of 1,027*10^7

b) at 25°C the rate of reaction increases by a factor of 1,777*10^5

Explanation:

using the Arrhenius equation

k= ko*e^(-Ea/RT)

where

k= reaction rate

ko= collision factor

Ea= activation energy

R= ideal gas constant= 8.314 J/mol*K

T= absolute temperature

for the uncatalysed reaction

k1= ko*e^(-Ea1/RT)

for the catalysed reaction

k2= ko*e^(-Ea2/RT)

dividing both equations

k2/k1= e^(-(Ea2-Ea1)/RT)

a) at 25°C

k2/k1 = e^(-(55kJ/mol-95kJ/mol)/(8.314J/mol*K*298K)* (1000J/kJ ) ) = 1,027*10^7

therefore at 25°C , k2/k1 = 1,027*10^6

b) at 125°C

k2/k1 = e^(-(55kJ/mol-95kJ/mol)/(8.314J/mol*K*298K)* (1000J/kJ ) ) = 1,777*10^5

therefore at 125°C , k2/k1 = 1,777*10^5

Note:

when the catalysts is incorporated, the catalysed reaction and the uncatalysed one run in parallel and therefore the real reaction rate is

k real = k1 + k2 = k2 (1+k1/k2)

since k2>>k1 → 1+k1/k2 ≈ 1 and thus k real ≈ k2

6 0
3 years ago
Where do reactions in a solid generally take place?
Sholpan [36]

Answer:

It's D.  On the surface of the solid.

Explanation:

If the reactant is a solid, the surface area of the solid will impact how fast the reaction goes. This is because the two types of molecule can only bump into each other at the liquid solid interface, i.e. on the surface of the solid. So the larger the surface area of the solid, the faster the reaction will be.

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Click Play and wait for the vibrations to stop. Suppose you were at the recording station when the earthquake hit. Based on the
tia_tia [17]

Answer:

vibrations and lots of girls screaming for sure

Explanation: and I dont know if this conts

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3 years ago
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