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anzhelika [568]

3 years ago

10

If measurements are made, then they are more precise on a larger scale.?

1 answer:

Anuta_ua [19.1K]3 years ago

7 0

Answer:

No.

Explanation:

According to the formula б/X=б/√n, as more measurements are made, the uncertainty gets smaller.

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Heterotrophic bacteria obtain food by

BARSIC [14]

Heterotrophic cells must ingest biomass to obtain their energy and nutrition. Heterotrophic microorganisms mostly feed upon dead plants and animals, and are known as decomposers. ... Some animals also specialize on feeding on dead organic matter, and are known as scavengers or detritivores. Hope this was helpful.

5 0

4 years ago

Consider the decomposition of a metal oxide to its elements, where M represents a generic metal. M 3 O 4 ( s ) − ⇀ ↽ − 3 M ( s )

Citrus2011 [14]

Answer:

a) ΔGrxn = 6.7 kJ/mol

b) K = 0.066

c) PO2 = 0.16 atm

Explanation:

a) The reaction is:

M₂O₃ = 2M + 3/2O₂

The expression for Gibbs energy is:

ΔGrxn = ∑Gproducts - ∑Greactants

Where

M₂O₃ = -6.7 kJ/mol

M = 0

O₂ = 0

$deltaG_{rxn} =((2*0)+(3/2*0))-(1*(-6.7))=6.7kJ/mol$

b) To calculate the constant we have the following expression:

$lnK=-\frac{deltaG_{rxn} }{RT}$

Where

ΔGrxn = 6.7 kJ/mol = 6700 J/mol

T = 298 K

R = 8.314 J/mol K

$lnK=-\frac{6700}{8.314*298} =-2.704\\K=0.066$

c) The equilibrium pressure of O₂ over M is:

$K=P_{O2} ^{3/2} \\P_{O2}=K^{2/3} =0.066^{2/3} =0.16atm$

3 0

3 years ago

This is all the water; the liquid portion of the planet.

Dominik [7]

The oceanic part of the earth is the liquid portion Of the planet

6 0

3 years ago

Movement of electrons about a central nucleus is a concept by whom?

Alenkasestr [34]

The answer is bohr hope this helps :)

5 0

3 years ago

Read 2 more answers

A gas has a volume of 490. mL at a temperature of -35.0 degrees C. What volume would the gas occupy at 42.0 degrees Celsius? Ple

miskamm [114]

Answer:

648.5 mL

Explanation:

Here we will assume that the pressure of the gas is constant, since it is not given or specified.

Therefore, we can use Charle's law, which states that:

"For an ideal gas kept at constant pressure, the volume of the gas is proportional to its absolute temperature"

Mathematically:

$\frac{V}{T}=const.$

where

V is the volume of the gas

T is its absolute temperature

The equation can be rewritten as

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where in this problem we have:

$V_1=490 mL$ is the initial volume of the gas

$T_1=-35.0^{\circ} + 273 = 238 K$ is the initial temperature

$T_2=42.0^{\circ}+273=315 K$ is the final temperature

Solving for V2, we find the final volume of the gas:

$V_2=\frac{V_1 T_2}{T_1}=\frac{(490)(315)}{238}=648.5 mL$

8 0

4 years ago