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Setler79 [48]
3 years ago
9

Please help me solve these chemical equations:

Chemistry
2 answers:
Reil [10]3 years ago
8 0
CaCO3 = CaO + CO2
I2 + 2Na2S2O3 = 2NaI + Na2S4O6
6Mg + P4 = 2Mg3P2
2Na + Cl2 = 2NaCl
soldier1979 [14.2K]3 years ago
7 0
This is impossible and confusing!!!
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Help me for brainlest pleaes
Tresset [83]
First option.

The male tails are more attractive because of their long feathers , meanwhile the female tails are shorter than expected!
6 0
3 years ago
Which one of the following statements about mixtures is correct [2] [3] The different substances in a mixture are always in a de
aivan3 [116]

Answer: Option (4) is the correct answer.

Explanation:

A mixture is defined as a substance that contains two or more different substance that are physically mixed with each other.

If solute particles are evenly distributed in a solvent then it is known as a homogeneous mixture.

For example, salt dissolved in water is a homogeneous mixture.

If solute particles are unevenly distributed into the solvent then it is known as a heterogeneous mixture.

For example, sand in water is a heterogeneous mixture.

Thus, we can conclude that the statement a mixture must contain at least two different substances, is correct about mixtures.

4 0
3 years ago
What is the name of P517
saul85 [17]

Answer:

Ryobi P517 18V Lithium Ion Cordless Brushless 2,900 SPM Reciprocating Saw w/ Anti-Vibration Handle and Tool-Less Blade Changing

Explanation:

8 0
3 years ago
How many grams of lithium sulfide must be dissolved in 1600.0 g water to make a 2.0 molal solution?
klasskru [66]
Molality is the number of moles of solutes in 1 kg of solvent.
the molality of solution to be prepared is 2.0 molal. 
therefore 2 moles in 1 kg water.
the mass of Li₂S required is - 46 g/mol x 2.0 mol = 92 g
the mass in 1 kg of solvent is - 92 g
Therefore mass of Li₂S required in 1600.0 g is - 92 g/kg x 1.6 kg = 147.2 g
7 0
2 years ago
Suppose the gas resulting from the sublimation of 1.00 g carbon dioxide is collected over water at 25.0◦c into a 1.00 l containe
jeyben [28]

Answer:

0.55 atm

Explanation:

First of all, we need to calculate the number of moles corresponding to 1.00 g of carbon dioxide. This is given by

n=\frac{m}{M_m}

where

m = 1.00 g is the mass of the gas

Mm = 44.0 g/mol is the molar mass of the gas

Substituting,

n=\frac{1.00 g}{44.0 g/mol}=0.0227 mol

Now we can find the pressure of the gas by using the ideal gas law:

pV=nRT

where

p is the gas pressure

V = 1.00 L is the volume

n = 0.0227 mol is the number of moles

R = 0.082 L/(atm K mol) is the gas constant

T = 25.0 C + 273 = 298 K is the temperature of the gas

Solving the formula for p, we find

p=\frac{nRT}{V}=\frac{(0.0227 mol)(0.082 L/(atm K mol))(298 K)}{1.00 L}=0.55 atm

8 0
3 years ago
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