Answer:
double replacement
synthesis
double replacement
i think this one is decomposition
synthesis
double replacement
single replacement
single replacement
double replacement
single replacement .....
hopefully i help
Answer:- The natural abundance of
is 0.478 or 47.8% and
is 0.522 or 52.2% .
Solution:- Average atomic mass of an element is calculated from the atomic masses of it's isotopes and their abundances using the formula:
Average atomic mass = mass of first isotope(abundance) + mass of second isotope(abundance)
We have been given with atomic masses for
and
as 150.919860 and 152.921243 amu, respectively. Average atomic mass of Eu is 151.964 amu.
Sum of natural abundances of isotopes of an element is always 1. If we assume the abundance of
as n then the abundance of
would be 1-n .
Let's plug in the values in the formula:

151.964=150.919860n+152.921243-152.921243n
on keeping similar terms on same side:


negative sign is on both sides so it is canceled:



The abundance of
is 0.478 which is 47.8%.
The abundance of
is = 
= 0.522 which is 52.2%
Hence, the natural abundance of
is 0.478 or 47.8% and
is 0.522 or 52.2% .
Answer:
1.402 * 10^2.
Explanation:
There are 3 digits before the decimal point so the exponent is 2.
Answer:
18.75 milligrams of active ingredient is the recommended dose for a child weighing 36–47 lbs .
Explanation:
Recommended dose of an antihistamine for a child weighing 36–47 lbs = 1.50 tsp
1 table spoon of antihistamine has 12.5 mg per 5 mL of dose.
Amount of dose in 1 teaspoon = 
Volume of 1 tsp = 5 ml
Volume of 1.50 teaspoon = 
Amount of antihistamine in 7.50 mL :

18.75 milligrams of active ingredient is the recommended dose for a child weighing 36–47 lbs .
Answer:
0.068 g
Explanation:
The equation that is used to determine the fraction q remaining in water of volume V₁ after n extractions of volume V₂ is:
qⁿ = (V₁/(V₁ + KV₂))ⁿ
Substituting in the values gives the fraction of caffeine left in the water phase:
q³ = (4.0mL/(4.0mL + 4.6(2.0mL))³ = 0.0278
The fraction of caffeine extracted into the methylene chloride phase is:
1 - 0.0278 = 0.972
The amount of caffeine extracted into the methylene chloride is:
(0.070g)(0.972) = 0.068 g