Answer:
Explanation:
Ba(s) + Mn²⁺ (aq,1M) → Ba²⁺ (aq,1M) + Mn(s)
Ba⁺²(aq) +2e → Ba(s) , E° = −2.90 V
Mn⁺²(aq) +2e → Mn(s), E⁰ =0.80 V
Anode reaction :
Ba(s) → Ba⁺²(aq) +2e E° = −2.90 V
Cathode reaction :
Mn⁺²(aq) +2e → Mn(s) E⁰ =0.80 V
Cell potential = Ecathode - Eanode
Ecell = .80 - ( - 2.90 )
Ecell = 3.7 V .
equilibrium constant ( K ) :
Ecell = .059 log K / n
n = 2
3.7 = .059 log K / 2
log K = 125.42
K = 2.63 x 10¹²⁵ .
Free energy change :
ΔG = - n F Ecell
= - 2 x 96500 x 3.7
= 714100 J
= 7.141 x 10⁵ J .
(a) 0.807 fraction of the sample will remain 3. 80 yr after its preparation of tritium.
<h3>What is half life?</h3>
Half life is the time taken for the radioactivity of a substance to fall to half its original value whereas mean life is average lifetime of all the nuclei of a particular unstable atomic species.
So if a radioactive element has a half life of one hour, this means that half of it will decay in one hour. After another hour, half of the remaining material will decay.
Example:
The radioactive isotope cobalt-60, which is used for radiotherapy, has, for example, a half-life of 5.26 years.
Tritium half life = 12.32 (T half)
Formula :
- N/N₀ = (1/2) ^ t/T (N/N₀ = Fraction ratio)
(a) 0.807 fraction of the sample will remain 3. 80 yr after its preparation of tritium.
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The molar mass of the protein is 45095 g/mol.
The mass of a sample of a chemical compound divided by the quantity, or number of moles in the sample, measured in moles, is known as the molar mass of that compound.
The expression of molar mass of protein is
M₂ = (W₂/P) (RT/V)
Given;
W₂ = 1.31g
P = 4.32 torr = 5.75 X 10⁻³ bar
R = 0.083 Lbar/mol/K
T = 25°C = 298.15 K
V = 125 ml = 0.125 L
Putting all the values in the above formula
M₂= (1.31 g/5.75 X 10⁻³ bar) X (0.083 Lbar/mol/K X 2)/0.125 L)
M₂ = 45095 g/mol
Thus, the molar mass of the protein is 45095 g/mol.
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