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Elanso [62]
3 years ago
11

Rosa was looking for patterns to help predict the products of chemical reactions. She recorded three similar decomposition react

ions in the table.
A 2-column table with 3 rows. The first column labeled reactants has entries 2 N a C l O subscript 3, 2 K C l O subscript 3, 2 L i C l O subscript 3. The second column labeled products has entries 2 N a C l + 3 O subscript 2, 3 O subscript 2 + 2 K C l, empty.

What products should she record in the last row of the table?

2LiCl + 3O2
3LiCl + 2O2
2LiO + 3Cl2
3LiO+ 2Cl2
Physics
2 answers:
dedylja [7]3 years ago
4 0

Answer:

It's A

Explanation:

Because I know it is

vlabodo [156]3 years ago
4 0

Answer:

a

Explanation:

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Alex17521 [72]

Answer: The control group is the part where you see what happens when you change a variable you want to study/examine. Basically, you need the control group because you need something to see what happens when you change something.

Hope this Helps! :))))

8 0
3 years ago
How is velocity different from speed?
enyata [817]

Velocity, unlike speed, includes a direction.

Velocity is a vector quantity which is defined by magnitude and direction.

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5 0
3 years ago
Read 2 more answers
A 6.00-kg crate is suspended from the end of a short vertical rope of negligible mass. An upward force F(t) is applied to the en
timofeeve [1]

Answer:

The magnitude of F when t=4 s=146.64 N

Explanation:

We are given that

Mass of crate,m=6.00 kg

Height of crate above its initial position is given by

y(t)=(2.80 m/s)t+(0.610 m/s^3)t^3

We have to find the magnitude of F when t=4.00 s

Differentiate w.r.t t

\frac{dy}{dt]=2.8+3(0.61)t^2

\frac{d^2y}{dt^2}=6(0.61)t

a(t)=\frac{d^2y}{dt^2}=6(0.61)t m/s

a(4)=6(0.61)(4)=14.64 m/s^2

Now, magnitude of force

F=m(a+g)=6(14.64+9.8)=146.64N

Hence, the magnitude of F when t=4 s=146.64 N

4 0
3 years ago
A rifle fires a 2.10 x 10^-2 kg pellet straight upward, because the pellet rests on a compressed spring when the trigger is is p
yKpoI14uk [10]

m = mass of pellet = 2.10 x 10⁻² kg

x = compression of spring at the time launch = 9.10 x 10⁻² m

h = height gained by the pellet above the initial position = 6.10 m

k = spring constant

using conservation of energy

spring potential energy = gravitational potential energy of pellet

(0.5) k x² = m g h

inserting the values

(0.5) k (9.10 x 10⁻²)² = (2.10 x 10⁻²) (9.8) (6.10)

k = 303.2 N/m

4 0
3 years ago
On a frictionless horizontal surface, a 1.50 kg mass traveling at 3.50 m/s collides with and sticks to a 3.00 kg mass that is in
My name is Ann [436]

Answer:

√ \frac{3}{5}  m

Explanation:

Hope it helps!.

4 0
3 years ago
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