Helppp mee pllleasse

What Is the definition of the term gravitational potential energy

OLga [1]

Answer:

Here are all the possible meanings and translations of the word gravitational energy. Gravitational energy is the potential energy associated with the gravitational field. This phrase is found frequently in scientific writings about quasars and other active galaxies. Quasars generate and emit their energy from a very small region.

Explanation:

4 0

3 years ago

Two billiard balls of equal mass move at right angles and meet at the origin of an xy coordinate system. Initially ball A is mov

frez [133]

Answer:

Speed of ball A after collision is 3.7 m/s

Speed of ball B after collision is 2 m/s

Direction of ball A after collision is towards positive x axis

Total momentum after collision is m×4·21 kgm/s

Total kinetic energy after collision is m×8·85 J

Explanation:

<h3>If we consider two balls as a system as there is no external force initial momentum of the system must be equal to the final momentum of the system</h3>

Let the mass of each ball be m kg

v $_{1}$ be the velocity of ball A along positive x axis

v $_{2}$ be the velocity of ball A along positive y axis

u be the velocity of ball B along positive y axis

Conservation of momentum along x axis

m×3·7 = m× v $_{1}$

∴ v $_{1}$ = 3.7 m/s along positive x axis

Conservation of momentum along y axis

m×2 = m×u + m× v $_{2}$

2 = u + v $_{2}$ → equation 1

<h3>Assuming that there is no permanent deformation between the balls we can say that it is an elastic collision</h3><h3>And for an elastic collision, coefficient of restitution = 1</h3>

∴ relative velocity of approach = relative velocity of separation

-2 = v $_{2}$ - u → equation 2

By adding both equations 1 and 2 we get

v $_{2}$ = 0

∴ u = 2 m/s along positive y axis

Kinetic energy before collision and after collision remains constant because it is an elastic collision

Kinetic energy = (m×2² + m×3·7²)÷2

= 8·85×m J

Total momentum = m×√(2² + 3·7²)

= m× 4·21 kgm/s

3 0

4 years ago

A system does 506 kj of work, and loses 266 kj of heat to the surroundings. what is the change in internal energy of the system?

babunello [35]

Answer:

The change in internal energy of the system = -772kJ

Explanation:

Given :

Heat lost by the system , a = -266KJ

Workdone by the system, W = -506KJ

The first law of thermodynamics states that:

Change in internal energy = q + w

Substituting values into the equation

Change in internal energy = (-266KJ) + (-506KJ)

Change in internal energy = -722KJ

7 0

3 years ago

Read 2 more answers

You and a friend are playing with a bowling ball to demonstrate some ideas of Rotational Physics. First, though, you want to cal

RideAnS [48]

Answer:

K_{total} = 19.4 J

Explanation:

The total kinetic energy that is formed by the linear part and the rotational part is requested

$K_{total} = K_{traslation} + K_{rotation}$

let's look for each energy

linear

$K_{traslation}$ = ½ m v²

rotation

$K_{rotation}$ = ½ I w²

the moment of inertia of a solid sphere is

I = 2/5 m r²

we substitute

$K_{total}$ = ½ mv² + ½ I w²

angular and linear velocity are related

v = w r

we substitute

K_{total} = ½ m w² r² + ½ (2/5 m r²) w²

K_{total} = m w² r² (½ + 1/5)

K_{total} = $\frac{7}{10}$ m w² r²

let's calculate

K_{total} = $\frac{7}{10}$ 6.40 16.0² 0.130²

K_{total} = 19.4 J

6 0

3 years ago

Hi, I have a question if I calculate the average force that must be exerted on a 0.145 kg baseball for me to give it an accelera

faltersainse [42]

Newton’s Second Law: Force = mass times acceleration.

F = 0.145 * 130

You would multiply to find the force required, not divide. Hope this helps!

7 0

3 years ago