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vesna_86 [32]
3 years ago
14

Give 3 importance of learning about fault​

Chemistry
1 answer:
Drupady [299]3 years ago
3 0

Answer:

These breaks, across which slip has occurred, are called faults. ... So understanding the types and patterns of ancient fault can help geologists to ... The faulting patterns can have enormous economic importance

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Two students are trying to figure out the Calories per gram of potato chips. They burn part of the potato chip and feel the heat
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2 years ago
8. __H2 + __O2-> __H2O
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Explanation:

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In the presence of an emulsifying agent, a mixture of oil and water becomes a _____.
Alex Ar [27]

Answer:

Colloidal dispersion or emulsion

Explanation:

The colloid of a liquid in liquid (both dispersed phase and dispersion medium are liquids) is known as emulsion or colloidal dispersion.

We know that oil and water are immiscible liquids. In order to make them miscible we have have add emulsifying agents.

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For example salts of fatty acids.

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7 0
3 years ago
Recall that your hypothesis is that these values are the fraction of atoms that are still radioactive after n half-life cycles.
Savatey [412]

0.5^{n} means 0.5 raise to the power of n. "To the power of" means an action of multiplication of 0.5 to n times.

The different values of n are given in the table. Substituting these values:

For A:

n = 1 (given)

0.5^{n} = 0.5^{1} = 0.5

For B:

n = 2 (given)

0.5^{n} = 0.5^{2} = 0.5\times 0.5 = 0.25

For C:

n = 3 (given)

0.5^{n} = 0.5^{3} = 0.5\times 0.5\times 0.5 = 0.125

For D:

n = 6 (given)

0.5^{n} = 0.5^{6} = 0.5\times 0.5\times 0.5\times 0.5\times 0.5\times 0.5= 0.015625

For E:

n = 8 (given)

0.5^{n} = 0.5^{8} = 0.5\times 0.5\times 0.5\times 0.5\times 0.5\times 0.5\times 0.5\times 0.5= 0.00390625

Hence, the values are:

A = 0.5

B = 0.25

C = 0.125

D = 0.015625

E = 0.00390625


4 0
2 years ago
Read 2 more answers
The gas in a balloon occupies 2.25 L at 298 K at what temperature will the balloon expand to 3.50 L
Alenkinab [10]

The temperature  that the balloon will  expand to 3.50 l is  463.56 K


<em><u> calculation</u></em>

by use of Charles law formula

that is  V1/T1 = V2/T2   where;

V1 = 2.25 l

T1= 298 k

V2= 3.50 l

T2=?

 make T2 the subject of the formula  T2 =(V2  xT1) /v1

T2= (3.50 l x 298 K)  /2.25 L  = 463.56 K

4 0
3 years ago
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