Answer:
PH₃.
Explanation:
Hello.
In this case, among the options:
PH₃, GaF₃, SF₂ and CO₂
We compute their molar masses by adding the atomic masses of the constituting elements by their subscripts:
Thus, the answer is PH₃.
Best regards.
They can both be gasses
Hope this helps
One benefit of this is that the weaknesses of some of their plans are covered by better plans. Another is that if the final plan doesn’t result, there are already many other ideas to go off of. A final benefit is that if the overall plan does work, it can still be easily improvised. Hope this helps! After all, this question is more opinion based.
Answer:
The mass of heavier isotope is 345.6 amu.
Explanation:
Given data:
atomic wight of compound = 342.38 amu
lighter isotope mass = 340.91 amu
abundance of lighter isotope = 68.322%
mass of heavier isotope = ?
Solution:
average atomic mass = ( % age abundance of lighter isotope × its atomic mass) + (% age abundance of heavier isotope × its atomic mass) / 100
percentage of heavier isotope = 100- 68.322 = 31.678
Now we will put the values in formula.
342.38 = (68.322× 340.91) + (31.678 × X) / 100
342.38 = 23291.65302 + (31.678 × X) / 100
342.38 × 100 = 23291.65302 + (31.678 × X)
34238 -23291.65302 = (31.678 × X)
10946.35 / 31.678 = X
345.6 = X
The mass of heavier isotope is 345.6 amu.
Answer:
3.01×10²³ atoms of calcium
Explanation:
number of moles = number of atoms/Avogadro's constant
n = N/NA
N = n×NA = 0.500 mol×6.02×10²³ mol^-1
N = 3.01×10²³ atoms of calcium
