A series RLC circuit with L = 12 mH, C = 3.5 mu or micro FF, and R = 3.3 ohm is driven by a generator with a maximum emf of 115
V and a variable angular frequency omega. (a) Find the resonant (angular) frequency omega0. rad/s [1.43 points] 0 attempt(s) made (maximum allowed for credit = 10) (b) Find Irms at resonance. A [1.43 points] 0 attempt(s) made (maximum allowed for credit = 10) When the angular frequency omega = 7600 rad/s, (c) Find the capacitive reactance XC in ohms. ohm [1.43 points] 0 attempt(s) made (maximum allowed for credit = 10) Find the inductive reactance XL in ohms. ohm [1.43 points] 0 attempt(s) made (maximum allowed for credit = 10) (d) Find the impedance Z. (Give your answer in ohms.) ohm [1.43 points] 0 attempt(s) made (maximum allowed for credit = 10) Find Irms. A [1.43 points] 0 attempt(s) made (maximum allowed for credit = 10) (e) Find the phase angle (in degrees). degrees
Compared with the amount of current in the filament of a lamp, the amount of current in the connecting wire is
D. the same.
As per the rule, the amount of current in devices connected in series is equal. here in the given situation , the wire is in series with the filament. that is the reason that the current in filament and wire is same.
