A diagram show how a converging lens can produce a real image and virtual image

Light undergoes refraction as it travels from water to glass. The refractive index of water = 1.33 and refractive index of glass

cestrela7 [59]

Answer: 28°

Explanation:

Snell's law n₁sinθ₁ = n₂sinθ₂

1.33sin32 = 1.5sinθ₂

θ₂ =28°

3 0

3 years ago

Fluid ounces measure _____?<br> Volume<br> Weight<br> Viscosity

ladessa [460]

Fluid ounces measure in volume

5 0

3 years ago

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A police car is driving down the street with it's siren on. You are standing still on the sidewalk beside the street. If the fre

diamong [38]

Answer:

A) 1568.60 Hz

Explanation:

This change is frequency happens due to doppler effect

The Doppler effect is the change in frequency of a wave in relation to an observer who is moving relative to the wave source

$f_(observed)=\frac{(c+-V_r)}{(C+-V_s)} *f_(emmited)\\$

where

C = the propagation speed of waves in the medium;

Vr= is the speed of the receiver relative to the medium,(added to C, if the receiver is moving towards the source, subtracted if the receiver is moving away from the source;

Vs= the speed of the source relative to the medium, added to C, if the source is moving away from the receiver, subtracted if the source is moving towards the receiver.

A) Here the Source is moving towards the receiver(C-Vs)

and the receiver is standing still (Vr=0) therefore the observed frequency should get higher

$f_(observed)=\frac{C}{C-V_s} *f_(emmited)\\=\frac{343}{343-15}*1500\\ =1568.60 Hz$

6 0

3 years ago

A new roller coaster contains a loop-the-loop in which the car and rider are completely upside down. If the radius of the loop i

Oduvanchick [21]

To solve this problem it is necessary to apply the concepts based on Newton's second law and the Centripetal Force.

That is to say,

$F_c = F_w$

Where,

$F_c =$ Centripetal Force

$F_w =$ Weight Force

Expanding the terms we have to,

$mg = \frac{mv^2}{r}$

$gr = v^2$

$v = \sqrt{gr}$

Where,

r = Radius

g = Gravity

v = Velocity

Replacing with our values we have

$v = \sqrt{(9.8)(11.8)}$

$v = 10.75m/s$

Therefore the minimum speed must the car traverse the loop so that the rider does not fall out while upside down at the top is 10.75m/s

5 0

3 years ago

You attach a meter stick to an oak tree, such that the top of the meter stick is 1.87 meters above the ground. Later, an acorn f

Verdich [7]

To solve this problem we will apply the concepts related to the kinematic equations of linear motion. We will calculate the initial velocity of the object, and from it, we will calculate the final position. With the considerations made in the statement we will obtain the total height. Initial velocity of the acorn,

$u = 0m/s$