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BARSIC [14]
2 years ago
11

A diagram show how a converging lens can produce a real image and virtual image​

Physics
1 answer:
Crazy boy [7]2 years ago
7 0

Answer:

True

Explanation:

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A car is moving with speed 60 m/s and acceleration 4 m/s2 at a given instant. (a) using a second-degree taylor polynomial, estim
pantera1 [17]

Answer:

Explanation:

Using second degree taylor polynomials

let S(t) be position function and set S(0)=0

where S(0) is the initial position

Then v(t) = S^i(t) and a(t)=S^{ii}(t)

we have v(0) = 60m/s, a(0) = 4m/s^2

so T_{2}(t) =S(0)+v(0)t+\frac{a(0)}{2} t^2\\\\\\=0+60t+\frac{4}{2} t^2\\\\T_{2}(t)=60t+2t^2\\\\S(1)=T_{2}(1)=60+2=62m

b.) yes

6 0
3 years ago
An alternating current is supplied to an electronic component with a rating that the voltage across it can never, even for an in
Vsevolod [243]

Answer:

A) V_{rms}=8\sqrt{2} V

Explanation:

Maximum voltage =V_{max}=16 V

Maximum voltage and rms voltage are related to each other by

V_{max}=V_{rms} \times \sqrt{2} \\V_{rms}=\frac{V_{max}}{ \sqrt{2}}\\V_{rms}=\frac{16}{\sqrt{2}} \\V_{rms}=8\sqrt{2} V

7 0
3 years ago
A physics student looks into a microscope and observes that small particles suspended in water are moving about in an irregular
Dominik [7]

Answer:

d. the actual motion is regular, but the speeds of particles are too large to observe the regular motion

Explanation:

The speeds of the particles are very large and comparatively the average  free path is very small . Therefore time taken in covering the free path ( path between two consecutive collision with medium particles ) is very small . Hence the st line  path covered by particles between two collision is less likely to be visible. Hence motion appears irregular or zig-zag.

6 0
3 years ago
I need help on 2/3 please asap thx ♥️
ch4aika [34]

<u>questions 2</u>

F=m

therefore

a=F/m

a=408/68

=6m/s^2.

5 0
3 years ago
A girl pulls her younger brother on a sled along a flat sidewalk (the total mass of the sled is 30kg). A frictional force of 50N
harkovskaia [24]

Answer:

6.13 s

219 N

Explanation:

Newton's law in the x direction:

∑F = ma

150 cos 30° N − 50 N = (30 kg) a

a = 2.66 m/s²

Δx = v₀ t + ½ at²

(50 m) = (0 m/s) t + ½ (2.66 m/s²) t²

t = 6.13 s

Newton's law in the y direction:

∑F = ma

Fn + 150 sin 30° N − (30 kg) (9.8 m/s²) = 0

Fn = 219 N

4 0
3 years ago
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