Bumper car A (281 kg) moving +2.82 m/s makes an elastic collision with bumper car B (209 kg) moving -1.72 m/s. What is the veloc
1 answer:
The velocity of B after elastic collision is 3.45m/s
This type of collision is an elastic collision and we can use a formula to solve this problem.
<h3>Elastic Collision</h3>The data given are;
- m1 = 281kg
- u1 = 2.82m/s
- m2 = 209kg
- u2 = -1.72m/s
- v1 = ?
Let's substitute the values into the equation.
From the calculation above, the final velocity of the car B after elastic collision is 3.45m/s.
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Answer :
Explanation :
The word kinematics means the study of motion. Kinematic variables gives the description of the motion of the body.
Displacement, Velocity, acceleration and time are associated with the motion of particle.
Wavenumber is defined as the frequency of wave, which is measured in cycles per unit distance.
Wave number is also defines as:
where, is wavelength
since,
So,
Where, is angular frequency and
is velocity of wave.
Hence, the relationship between the angular wavenumber k and and kinamatic variable V is
In a collision an object experiences impulses, this impulse can be determined by the product of net force exerted upon it in the specific course of time.
<u>Explanation:</u>
An object experiences impulse due to the force exerted upon it in a particular time period.
i.e.
Where,
F - Force acted upon the object
- time interval for which the force act
According to the definition of Impulse, it is the integral of force (F) that acts upon any object over a time interval ∆t. It produces an equivalent change in the momentum and that too in the same direction as of the applied force (F).
Therefore, in order to find the impulse on an object, we have to find the force acted on it in a specific time interval.