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3 years ago

Why is your physical and mental health important?

Physics

2 answers:

katovenus [111]3 years ago

6 0

Answer:

Both maths are very important to our daily lives. Physical math helps us understand the reality of life. Learning to do certain math strategies is the first stage to finding answers to problems. Mental math can help us get answers faster through memory. This can help improve strategic methods and strengthen our minds.

Alex73 [517]3 years ago

4 0

Answer: Mental health and physical health are very closely connected. Mental health plays a major role in your ability to maintain good physical health. Mental illnesses, such as depression and anxiety, affect your ability to participate in healthy behaviors.

Explanation: Hope this helped. Have a great day!!!!

You might be interested in

Magnitudes cuantitativas<br> ejemplos

Kipish [7]

Where is the Picture?

7 0

2 years ago

In a certain time period a coil of wire is rotated from one orientation to another with respect to a uniform 0.38-T magnetic fie

juin [17]

<h2>The emf produced is 7.2 V</h2>

Explanation:

When coil is placed in the magnetic field , the flux attached with it can be found by the relation . Flux Ф = the dot product of magnetic field and area of coil .

Thus Ф = B A cosθ

here B is magnetic field strength and A is the area of coil .

The angle θ is the angle between coil and field direction .

When coil rotates , the angle varies . By which the flux varies . The emf is produced in coil due to variation of flux . The relation for this is

The emf produced ξ = - $\frac{d\phi}{dt}$ = B A sinθ $\frac{d\theta}{dt}$

Now in the given problem

5 = 0.38 x A x $\frac{d\theta}{dt}$ I

Now if the magnetic field is 0.55 T and all the other terms are same , the emf produced

ξ = 0.55 x A x $\frac{d\theta}{dt}$ Ii

dividing II by I , we have

$\frac{\xi}{5}$ = $\frac{0.55}{0.38}$ = 1.45

or ξ = 7.2 V

6 0

3 years ago

Air is compressed adiabatically in a piston-cylinder assembly from 1 bar, 300 K to 10 bar, 600 K. The air can be modeled as an i

julia-pushkina [17]

Answer:

1) the entropy generated is Δs= 0.0363 kJ/kg K

2) the minimum theoretical work is w piston = 201.219 kJ/kg

Explanation:

1) From the second law of thermodynamics applied to an ideal gas

ΔS = Cp* ln ( T₂/T₁) - R ln (P₂/P₁)

and also

k= Cp/Cv , Cp-Cv=R → Cp*( 1-1/k) = R → Cp= R/(1-1/k)= k*R/(k-1)

ΔS = k*R/(k-1)* ln ( T₂/T₁) - R ln (P₂/P₁)

where R= ideal gas constant , k= adiabatic coefficient of air = 1.4

replacing values (k=1.4)

ΔS = k*R/(k-1)* ln ( T₂/T₁) - R ln (P₂/P₁)

ΔS = 1.4/(1.4-1) *8.314 J/mol K * ln( 600K/300K) - 8.314 J/mol K * ln (10 bar/ 1bar)

ΔS = 1.026 J/ mol K

per mass

Δs = ΔS / M

where M= molecular weight of air

Δs = 1.026 J/ mol K / 28.84 gr/mol = 0.0363 J/gr K = 0.0363 kJ/kg K

2) The minimum theoretical work input is carried out under a reversible process. from the second law of thermodynamics

ΔS =∫dQ/T =0 since Q=0→dQ=0

then

0 = k*R/(k-1)* ln ( T₂/T₁) - R ln (P₂/P₁)

T₂/T₁ = (P₂/P₁)^[(k-1)/k]

T₂ = T₁ * (P₂/P₁)^[(k-1)/k]

replacing values

T₂ = 300K * ( 10 bar/1 bar)^[0.4/1.4] = 579.2 K

then from the first law of thermodynamics

ΔU= Q - Wgas = Q + Wpiston ,

where ΔU= variation of internal energy , Wgas = work done by the gas to the piston , Wpiston = work done by the piston to the gas

since Q=0

Wpiston = ΔU

for an ideal gas

ΔU= n*Cv*(T final - T initial)

and also

k= Cp/Cv , Cp-Cv=R → Cv*( k-1) = R → Cv= R/(k-1)

then

ΔU= n*R/(k-1)*(T₂ - T₁)

W piston = ΔU = n*R/(k-1)*(T₂ - T₁)

the work per kilogram of air will be

w piston = W piston / m = n/m*R/(k-1)*(T₂ - T₁) = (1/M*) R/(k-1)*(T₂ - T₁) ,

replacing values

w piston = (1/M*) R/(k-1)*(T₂ - T₁) = 1/ (28.84 gr/mol)* 8.314 J/mol K /0.4 * ( 579.2 K - 300 K) = 201.219 J/gr = 201.219 kJ/kg

6 0

3 years ago

A pendulum has 201 J of potential energy at the highest point of its swing. How much kinetic energy will it have at the bottom o

malfutka [58]

<h2>Hello!</h2>

The answer is: 201 J of kinetic energy.

The motion of a pendulum (with no friction considered) is a continuous exchange between potential energy and kinetic energy.

So, at the highest point of its swing, the potential energy will be the maximum potential energy that the pendulum can have and the kinetic energy will be 0 since at max height the speed tends to 0.

On the opposite side, when the pendulum is at the bottom (the lowest point of its swing) the potential energy will be the minimum (tends to 0) but the kinetic energy will be the maximum.

Also, in the pendulum motion, the total energy is conserved, meaning that:

$PE_{h} +KE_{h}=PE_{l} +KE_{l}\\PE=mgh\\KE=\frac{1mv^{2} }{2}$