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bonufazy [111]
3 years ago
13

Why is your physical and mental health important?

Physics
2 answers:
katovenus [111]3 years ago
6 0

Answer:

Both maths are very important to our daily lives. Physical math helps us understand the reality of life. Learning to do certain math strategies is the first stage to finding answers to problems. Mental math can help us get answers faster through memory. This can help improve strategic methods and strengthen our minds.

Alex73 [517]3 years ago
4 0

Answer: Mental health and physical health are very closely connected. Mental health plays a major role in your ability to maintain good physical health. Mental illnesses, such as depression and anxiety, affect your ability to participate in healthy behaviors.

Explanation: Hope this helped. Have a great day!!!!

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If the wave speed stays the same, which of the following decreases as the frequency increases?
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1) The electric force changes by a factor of 25

2) The electric force changes by a factor of 16/9

Explanation:

1)

The magnitude of the electrostatic force between two charges is given by Coulomb's law:

F=k\frac{q_1 q_2}{r^2}

where:

k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q_1, q_2 are the two charges

r is the separation between the two charges

In this problem, let's call F the initial force between the two charges when they are at a distance of r.

Later, the distance is changed by a factor of 5. Let's assume it has been increased to a factor of 5: so the new distance is

r' = 5r

Therefore, the new force between the charges is:

F' = k' \frac{q_1 q_2}{r'^2}=k' \frac{q_1 q_2}{(5r)^2}=\frac{1}{25}(k' \frac{q_1 q_2}{r'^2})=\frac{F}{25}

So, the force has changed by a factor of 25.

2)

The original force between the two charges is

F=k\frac{q_1 q_2}{r^2}

In this problem, we have:

- The distance between the charges is changed by a factor of 6:

r' = 6r

- The charges are both changed by a factor of 8:

q_1' = 8q_1

q_2' = 8q_2

Substituting into the equation, we find the new force:

F' = k' \frac{q_1' q_2'}{r'^2}=k' \frac{(8q_1) (8q_2)}{(6r)^2}=\frac{64}{36}(k' \frac{q_1 q_2}{r'^2})=\frac{16}{9}F

So, the force has changed by a factor of 16/9.

Learn more about electric force:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

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3 years ago
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