A parachutist bails out and freely falls 50 m. Then the parachute opens, and thereafter she deceler- ates at 2.0 m/s2. She reach
1 answer:
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Given:
F = ax
where
x = distance by which the rubber band is stretched
a = constant
The work done in stretching the rubber band from x = 0 to x = L is
![W=\int_{0}^{L} Fdx = \int_{0}^{L}ax \, dx = \frac{a}{2} [x^{2} ]_{0}^{L} = \frac{aL^{2}}{2}](https://tex.z-dn.net/?f=W%3D%5Cint_%7B0%7D%5E%7BL%7D%20Fdx%20%3D%20%5Cint_%7B0%7D%5E%7BL%7Dax%20%5C%2C%20dx%20%3D%20%5Cfrac%7Ba%7D%7B2%7D%20%20%5Bx%5E%7B2%7D%20%5D_%7B0%7D%5E%7BL%7D%20%3D%20%20%5Cfrac%7BaL%5E%7B2%7D%7D%7B2%7D%20)
Answer:
F = ax
where
x = distance by which the rubber band is stretched
a = constant
The work done in stretching the rubber band from x = 0 to x = L is
Answer:
Answer:
The force is 272.73 newtons
Explanation:
We're going to use impulse-momentum theorem that states impulse is the change on the linear momentum this is:
(1)
Impulse is also defined as average force times the time the force is applied:
(2)
By (2) on (1):
solving for :
(3)
We already know Δt is equal to 0.22 s, all we should do now is to find and put on (3) (
the initial momentum and
the final momentum). Linear momentum is defined as
, using that on (3):
(4)
Velocity (v) are vectors so direction matters, if positive direction is the right direction and negative direction left and
so (4) becomes:
(5)
Using (5) on (3):