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sdas [7]
3 years ago
10

PLEASE HELP!! WILL GIVE 5 STARS, A THANKS AND BRAINLIEST

Chemistry
1 answer:
Neporo4naja [7]3 years ago
7 0

Answer:

"Carbon dioxide (CO2) is one of a number of gases that are transparent to the visible light falling on the Earth from the Sun, but absorb the infra-red radiation (heat) emitted by the warm surface of the Earth, preventing its loss into space. During the geological history of the Earth the level of atmospheric CO2 has varied considerably and this has had an impact on the global temperature. A significant amount of this atmospheric carbon was sequestered or (removed from the atmosphere) and turned into inert material (coal, and oil) typically 300-360 Million years ago. All of the global ecosystems and species have adapted to a lower level of atmospheric CO2 and critically, human civilisation has also grown since that period.  Since the industrial revolution humans have been burning sequestered CO2 in the form of coal, oil, and natural gas which has the result of releasing energy but also releases CO2 back into the atmosphere".

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Explanation:

The given data is as follows.

Molecular weight of azulene = 128 g/mol

Hence, calculate the number of moles as follows.

      No. of moles = \frac{mass}{\text{molecular weight}}

                            = \frac{0.392 g}{128 g/mol}

                            = 0.0030625 mol of azulene

Also,    -Q_{rxn} = Q_{solution} + Q_{cal}

       Q_{rxn} = n \times dE

         Q_{solution} = m \times C \times (T_{f} - T_{i})

              Q_{cal} = C_{cal} \times (T_{f} - T_{i})

Now, putting the given values as follows.    

     Q_{solution} = 1.17 \times 10^{3} g \times 10^{3} \times 4.184 J/g^{o}C \times (27.60 - 25.20)^{o}C

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So,  Q_{cal} = 786 J/^{o}C \times (27.60 - 25.20)^{o}C

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Therefore, heat of reaction will be calculated as follows.

        -Q_{rxn} = (11748.67 + 1886.4) J

                      = 13635.07 J

As,  Q_{rxn} = n \times dE

          13635.07 J = -n \times dE

                dE = \frac{13635.07 J}{0.0030625 mol}

                     = 4452267.75 J/mol

or,                 = 4452.26 kJ/mol       (as 1 kJ = 1000 J)

Thus, we can conclude that \Delta E for the given combustion reaction per mole of azulene burned is 4452.26 kJ/mol.

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