Answer:
A)cout<<setw(9)<<fixed<<setprecision(2)<<34.789;
B)cout<<setw(5)<<fixed<<setprecision(3)<<7.0;
C)cout<<fixed<<5.789E12;
D)cout<<left<<setw(7)<<67;
Explanation:
Stream Manipulators are functions specifically designed to be used in conjunction with the insertion (<<) and extraction (>>) operators on stream objects in C++ programming while the 'cout' statement is used to display the output of a C++to the standard output device.
setw: used to specify the minimum number of character positions on the output field
setprecision: Sets the decimal precision to be used to format floating-point values on output operations.
fixed: is used to set the floatfield format flag for the specified str stream.
left: adjust output to the left.
A) To display the number 34.789 in a field of eight spaces with two decimal places of precision. cout<<setw(9)<<fixed<<setprecision(2)<<34.789;
B) To display the number 7.0 in a field of six spaces with three decimal places of precision. cout<<setw(5)<<fixed<<setprecision(3)<<7.0;
C) To print out the number 5.789e+12 in fixed-point notation. cout<<fixed<<5.789E12;
(D) To display the number 67 left-justified in a field of six spaces. cout<<left<<setw(7)<<67;
Answer:
The inlet match number is 3.42.
Explanation:
Answer:
Block design test. A block design test is a subtest on many IQ test batteries used as part of assessment of human intelligence. It is thought to tap spatial visualization ability and motor skill.
Explanation:
Answer:
The correct answers are:
a. % w = 33.3%
b. mass of water = 45g
Explanation:
First, let us define the parameters in the question:
void ratio e = 
= 
Specific gravity 
= 
% Saturation S = 
× 
= 
× 
water content w = 
= 
a) To calculate the lower and upper limits of water content:
when S = 100%, it means that the soil is fully saturated and this will give the upper limit of water content.
when S < 100%, the soil is partially saturated, and this will give the lower limit of water content.
Note; S = 0% means that the soil is perfectly dry. Hence, when s = 1 will give the lowest limit of water content.
To get the relationship between water content and saturation, we will manipulate the equations above;
w = 
Recall; mass = Density × volume
w = 
From eqn. (2) = 
∴ 
putting eqn. (6) into (5)
w = 
Again, from eqn (1)
substituting into eqn. (7)
∴ 
With eqn. (7), we can calculate
upper limit of water content
when S = 100% = 1
Given, 
∴
∴ %w = 33.3%
Lower limit of water content
when S = 1% = 0.01
∴ % w = 0.33%
b) Calculating mass of water in 100 cm³ sample of soil (
)
Given, 
, S = 50% = 0.5
%S = 
× = 
×
0.50 = 
mass of water = 
