Answer:
For Figure Below, if the elevation of the benchmark A is 25.00 m above MSL:
1. Using the Rise and Fall Method, find the reduced level for all points. (Construct the Table)
2. Using HPC Method, find the reduced level for all points. ( Construct the Table).
3. Show all required Arithmetic checks for your work. For Item 1 and 2.
4. What is the difference in height between points H and D?
5. What is the gradient of the line connecting A and J, knowing that horizontal distance = 200
m.
Answer:
Encouraging your preschooler’s creative play
For your preschooler, time, materials and space to be creative are very important.
Preschoolers like to be spontaneous in their creative play, so it’s good to follow your child’s lead. But there’ll also be times when your child wants you to be more involved in her creative activities. By being actively involved, you can develop your child’s skills and understanding.
Answer:
Electrons in atoms can act as our charge carrier, because every electron carries a negative charge. If we can free an electron from an atom and force it to move, we can create electricity.
Answer:
The major effects of ice accretion on the aircraft is that it disturbs the flow of air and effects the aircraft's performance.
Explanation:
The ice accretion effects the longitudinal stability of an aircraft as:
1. The accumulation of ice on the tail of an aircraft results in the reduction the longitudinal stability and the elevator's efficacy.
2. When the flap is deflected at 
with no power there is an increase in the longitudinal velocity.
3. When the angle of attack is higher close to the stall where separation occurs in the early stages of flow, the effect of ice accretion are of importance.
4. When the situation involves no flap at reduced power setting results in the decrease in aircraft's longitudinal stability an increase in change in coefficient of pitching moment with attack angle.
Answer:
(c) 5.71 V
Explanation:
The circuit can be redrawn to a Thevenin equivalent that is 6V through a 5-ohm resistor into a 100-ohm load. Then the voltage at the load is ...
(6 V)(100/(100 +5) ≈ 5.71 V
