Ehheem✔️
Explanation:
✔️✖️✔️✖️✔️✖️
Answer:
Gravitational; strongest; facing; closer; near side; toward.
Explanation:
The gravitational attraction between the Earth and the moon is strongest on the side of the Earth that happens to be facing the moon, simply because it is closer. This attraction causes the water on this “near side” of Earth to be pulled toward the moon. These forces of attraction and inertia tends to keep the water in place and consequently, leads to a bulge of water on the near side with respect to the moon.
Also, you should note that what is responsible for the moon being in orbit around the Earth is the gravitational force of attraction between the two planetary bodies (Earth and Moon).
A type of shoot in which continuous lighting used is: 1) studio.
<h3>What is a photoshoot?</h3>
A photoshoot simply refers to a photography session which typically involves the use of digital media equipment such as a camera, to take series of pictures (photographs) of models, group, things or places, etc., especially by a professional photographer.
<h3>The types of shoot.</h3>
Basically, there are four main type of shoot and these include the following:
In photography, a type of shoot in which continuous lighting used is studio because it enhances the photographs.
Read more on photography here: brainly.com/question/24582274
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Answer:
![M=0.0411 kg/h or 4.1*10^{-2} kg/h](https://tex.z-dn.net/?f=M%3D0.0411%20kg%2Fh%20or%204.1%2A10%5E%7B-2%7D%20kg%2Fh)
Explanation:
We have to combine the following formula to find the mass yield:
![M=JAt](https://tex.z-dn.net/?f=M%3DJAt%20)
![M=-DAt(ΔC/Δx)](https://tex.z-dn.net/?f=M%3D-DAt%28%CE%94C%2F%CE%94x%29)
The diffusion coefficient : ![D=6.0*10^{-8} m/s^{2}](https://tex.z-dn.net/?f=D%3D6.0%2A10%5E%7B-8%7D%20m%2Fs%5E%7B2%7D)
The area : ![A=0.25 m^{2}](https://tex.z-dn.net/?f=A%3D0.25%20m%5E%7B2%7D)
Time : ![t=3600 s/h](https://tex.z-dn.net/?f=t%3D3600%20s%2Fh)
ΔC: ![(0.64-3.0)kg/m^{3}](https://tex.z-dn.net/?f=%280.64-3.0%29kg%2Fm%5E%7B3%7D)
Δx: ![3.1*10^{-3}m](https://tex.z-dn.net/?f=3.1%2A10%5E%7B-3%7Dm)
Now substitute the values
![M=-DAt(ΔC/Δx)](https://tex.z-dn.net/?f=M%3D-DAt%28%CE%94C%2F%CE%94x%29)
![M=-(6.0*10^{-8} m/s^{2})(0.25 m^{2})(3600 s/h)[(0.64-3.0kg/m^{3})(3.1*10^{-3}m)]](https://tex.z-dn.net/?f=M%3D-%286.0%2A10%5E%7B-8%7D%20m%2Fs%5E%7B2%7D%29%280.25%20m%5E%7B2%7D%29%283600%20s%2Fh%29%5B%280.64-3.0kg%2Fm%5E%7B3%7D%29%283.1%2A10%5E%7B-3%7Dm%29%5D)
![M=0.0411 kg/h or 4.1*10^{-2} kg/h](https://tex.z-dn.net/?f=M%3D0.0411%20kg%2Fh%20or%204.1%2A10%5E%7B-2%7D%20kg%2Fh)
Answer:
The current through the coil is 2.05 A
Explanation:
Given;
number of turns of the coil, N = 1
radius of the coil, r = 9.8 cm = 0.098 m
magnetic moment of the coil, P = 6.2 x 10⁻² A m²
The magnetic moment is given by;
P = IA
Where;
I is the current through the coil
A is area of the coil = πr² = π(0.098)² = 0.03018 m²
The current through the coil is given by;
I = P / A
I = (6.2 x 10⁻² ) / (0.03018)
I = 2.05 A
Therefore, the current through the coil is 2.05 A