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svp [43]
3 years ago
6

B is the desired product, and X and Y are foul pollutants that are expensive to get rid of. The specific reaction rates are at 2

7C. The reaction system is to be operated at 27C and 4 atm. Pure A enters the system at a volumetric flow rate of 10 dm3/min.
(a) Sketch the instantaneous selectivities (SBAoSB/Y, and SBXY-ry(rxtrY)) as a function of the concentration of CA
(b) Consider a series of reactors. What should be the volume of the first reactor?
Engineering
1 answer:
AURORKA [14]3 years ago
3 0

Answer:

See attachment for detailed answer.

Explanation:

Download pdf
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A disk brake has two pads which cover 45 degrees of the disk. The outside radius is 6.0 inch and the inside radius is 4.0 inch.
Alona [7]

Answer:

f = 628.32 lb

t = 2513.28 lb-inc

Explanation:

given data:

θ = 45°

outside radius = 6 inch

inside radius = 4 inch

coefficient of friction = 0.4

max pressure = 100 psi

a) determine force required for applying one pad

f =    \frac{\theta }{360}* 2\pi *p_{max}*r_{i}(r_{o}-r_{i})

f = \frac{45 }{360}* 2\pi *100*4(6-4)

f = 628.32 lb

b) torque capacity (t)

t = \mu *f*r_{average}^{}

t = 0.4 *628.32*5

torque = 1256.64 lb-inc

for both pad = 2 * 1256.64 =2513.28 lb-inc

7 0
3 years ago
Might give brainliest
zepelin [54]

Answer:

Blissymbols

Explanation:

Blissymbols is a constructed language with hundreds of basic symbols that represent words.

7 0
3 years ago
Calculate the reactions at 4 ends (supports) of this bookshelf. Assume that the weight of each book is approximately 1 lb. The w
hoa [83]

Answer:

R = 4.75 lb  (↑)

Explanation:

Number of books = n = 19

Weight of each book = W = 1 lb

Length of the bookshelf = L = 40 inches

We can get the value of the distributed load as follows

q = n*W/L = 19*1 lb/ 40 inches = 0.475 lb/in

then the reactions at 4 ends (supports) of the bookshelf are

R = (q/2)/2 = 4.75 lb

We can see the bookshelf in the pic.

8 0
3 years ago
An air conditioner removes heat steadily from a house at a rate of 750 kJ/min while drawing electric power at a rate of 6 kW. De
Paraphin [41]

Answer:

a. 2.08, b. 1110 kJ/min

Explanation:

The power consumption and the cooling rate of an air conditioner are given. The COP or Coefficient of Performance and the rate of heat rejection are to be determined. <u>Assume that the air conditioner operates steadily.</u>

a. The coefficient of performance of the air conditioner (refrigerator) is determined from its definition, which is

COP(r) = Q(L)/W(net in), where Q(L) is the rate of heat removed and W(net in) is the work done to remove said heat

COP(r) = (750 kJ/min/6 kW) x (1 kW/60kJ/min) = 2.08

The COP of this air conditioner is 2.08.

b. The rate of heat discharged to the outside air is determined from the energy balance.

Q(H) = Q(L) + W(net in)

Q(H) = 750 kJ/min + 6 x 60 kJ/min = 1110 kJ/min

The rate of heat transfer to the outside air is 1110 kJ for every minute.

5 0
3 years ago
A pressure gage at the inlet to a gas compressor indicates that the gage pressure is 40.0 kPa. Atmospheric pressure is 1.01 bar.
bonufazy [111]

Answer:

Given

inlet Pga =40kpa = 40000pa

Patm=1.01bar = 1.01 x 100000pa =101000pa

exit Pab= 6.5 (inlet Pab)

But generally, Pab = Patm + Pga

1. the absolute pressure of the gas at the inlet, inlet Pab?

inlet Pab = Patm + inlet Pga

            = 101000pa + 40000pa = 141kpa

the absolute pressure of the gas at the inlet, inlet Pab = 141kpa

2. the gage pressure of the gas at the exit? exit Pga?

exit Pab = Patm + exit Pga

exit Pga = exit Pab - Patm

             = (6.5 x 141kpa) - 101kpa

              = 815.5kpa

the gage pressure of the gas at the exit exit Pga=815.5kpa

5 0
3 years ago
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