Question

List, in ascending order, the cutoff frequencies for the first ten modes of a rectangular waveguide, normalized to the cutoff frequency of the TE10 mode. (That is, for each mode, you will be calculating the cutoff frequency of that mode divided by the cutoff frequency of the TE10 mode.) Assume that a = 2b. Give numerical values for the normalized cutoff frequencies and clearly indentify the mode number and type (TM or TE) for each mode. (Note that some modes may have the same cutoff frequency.)

Answer 1

Answer:

Fcte10 < Fcte01 = Fcte0 < Fctm11 < Fcte21 = Fctm21 < Fcte12 = Fctm12 < Fcte22

Explanation:

Assuming a = 2b

Attached below is the required steps to the solution

The cutoff frequencies for the first ten modes of a rectangular waveguide listed in ascending order  is :

Fcte10 < Fcte01 = Fcte0 < Fctm11 < Fcte21 = Fctm21 < Fcte12 = Fctm12 < Fcte22