Answer:
R = 31.9 x 10^(6) At/Wb
So option A is correct
Explanation:
Reluctance is obtained by dividing the length of the magnetic path L by the permeability times the cross-sectional area A
Thus; R = L/μA,
Now from the question,
L = 4m
r_1 = 1.75cm = 0.0175m
r_2 = 2.2cm = 0.022m
So Area will be A_2 - A_1
Thus = π(r_2)² - π(r_1)²
A = π(0.0225)² - π(0.0175)²
A = π[0.0002]
A = 6.28 x 10^(-4) m²
We are given that;
L = 4m
μ_steel = 2 x 10^(-4) Wb/At - m
Thus, reluctance is calculated as;
R = 4/(2 x 10^(-4) x 6.28x 10^(-4))
R = 0.319 x 10^(8) At/Wb
R = 31.9 x 10^(6) At/Wb
Answer:
Explanation:
The answer to the given problem is been solved in the fine attached below.
Answer:
D is the correct choice.
Explanation:
I'm assuming that this is probably a phase in the textbook or progarm you are studying, and this is just a matter of reading thoroughly.
Engineers usually benefit from catching a mistake, and would also benfit from keeping record of a misstep in order to remain clear of that mistake in the future.
Have a great day, and mark me brainliest if I am most helpful!
:)
Answer:
0.3129
Explanation:
Calculate The minimum fiber volume fraction using the relation below
E = x * E1 + ( 1 - x ) E2 ------ ( 1 )
given that :
E = 83 GPa , x = ?
E1 = 260 GPa , E2 = 2.4 GPA
Insert values back into equation 1
Then ; 80.6 = 257.6 x
∴ x ( volume fraction ) = 80.6 / 257.6 = 0.3129
Answer:
vehicle density = 28.205 veh/mile
flow rate = 0.909 veh/hr
Explanation:
given data
count n = 21
distance = 0.78 miles
speed = 52 mph
solution
we get here vehicle density that is express as
vehicle density = n ÷ distance ...............1
vehicle density = ( 21 + 1 ) ÷ 0.78
vehicle density k = 28.205 veh/mile
and
now we get here flow rate that is express as
flow rate = k × vs .................2
flow rate = 28.205 × ( 52 × 0.00062 ÷ 1m )
flow rate = 0.909 veh/hr
