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lapo4ka [179]
2 years ago
15

The average velocity of an object over 6.0 seconds interval is 2 m/s what is the total distance traveled and M by the object doi

ng this time interval
Physics
1 answer:
lina2011 [118]2 years ago
8 0

Answer:

<h2>The answer is 12 m</h2>

Explanation:

The distance covered by an object given it's velocity and time taken can be found by using the formula

distance = velocity × time

From the question we have

distance = 2 × 6

We have the final answer as

<h3>12 m</h3>

Hope this helps you

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Answer:

a) vB = 10.77 ft/s

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vA <em>lin</em> = 5 ft/s

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vB = ?

rB = 1 ft

W = ?

We can apply The law of conservation of angular momentum

L<em>in</em> = L<em>fin</em>

m*vA*rA =  m*vB*rB    ⇒    vB = vA*rA / rB

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then we get

vB = √(vB tang² + vB rad²)   ⇒   vB = √((10 ft/s)² + (4 ft/s)²)

⇒   vB = 10.77 ft/s

b) W = ΔK = K<em>B</em> - K<em>A</em> = 0.5*m*vB² - 0.5*m*vA²

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⇒     W = 11.30 lb*ft

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