What you know:
Vi=0m/s
Vf=143.8m/s
A=-9.8m/s
d=???
Use the equation Vf^2=Vi^2+2A(d)
Rearrange to isolate d: d=Vf^2/2A
d=(143.8)^2/2(-9.8)
d=20678.4/-19.6
d=-1055m
The tank was released from a height of 1055m
micrometer is used to measure the diameter of a thin wire
Answer:
Magnitude of the force between the charges is F = 1.92×10^20N
Explanation:
Given the magnitude of force according to coulombs law
F =K[(q1*q2)/r2]
Where q1 and q2 are the charges
r is the distance between the charges
K is the coulombs constant
Substituting the given values, we have;
F = 8.98×10^9 × 1.5×10^6 × 3.2×10^4/1.5²
F = 43.1×10^19/2.25
F = 19.16×10^19N
F = 1.92×10^20N
The answer is a. generator!
Answer:
v = 0.22 c and wavelength is decrease so galaxy A is move away from stationary galaxy
v = 0.095 c and wavelength is increase so galaxy B come toward stationary galaxy
Explanation:
Given data
found = 500 nm
shifted A = 400 nm
shifted B = 550 nm
to find out
How fast and in what direction is galaxy
solution
we use here formula that is
(λ) shifted = √(1-β / 1+β) (λ)found
1-β / 1+β = (4/5)² ..................1
1-β / 1+β = 16 / 25
β = 0.22
v/c = 0.22
v = 0.22 c
here wavelength is decrease so galaxy A is move away from stationary galaxy
and
here according to equation 1
and we use shifted 550 nm
so
1-β / 1+β = (5.5/5)²
1-β / 1+β = 30.25 / 25
β = 0.095
so v/c = 0.095
v = 0.095 c
here wavelength is increase so galaxy B come toward stationary galaxy
