To solve this problem we will apply the concepts related to Ohm's law and Electric Power. By Ohm's law we know that resistance is equivalent to,

Here,
V = Voltage
I = Current
While the power is equivalent to the product between the current and the voltage, thus solving for the current we have,


Applying Ohm's law


Therefore the equivalent resistance of the light string is 
Answer:
Pressure difference between Top and Bottom of the cylinder is given as

Explanation:
As we know that the force due to pressure is balanced by the weight of the cylinder
So we will have

so we have

so we have

so we have

Given :
An object with a volume of 9 cm³ is completely submerged in the water.
To Find :
How much water is displaced by the object.
Solution :
According to Archimedes' principle, the amount of volume displaced of fluid when an object is fully and partially submerged into that is equal to the volume of the object below the surface of liquid.
Now, it is given that object is fully submerged into water.
Therefore, volume of water displaced by the object is 9 cm³.
I=120 V/20 ohms
=6.0 A
SO the answer would be <span>A. 6.00 A</span>