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Alex17521 [72]
3 years ago
15

Two identical balls balls P and Q, each of mass 0.20 g, carry identical charges and are suspended by two threads of equal length

. The balls position themselves at equilibrium such that the angle between the threads is 60_{o}.If the distance between the the balls is 0.5m, find the charge on each of them. Take g = 9.8 m/s^{2}

Physics
1 answer:
Elden [556K]3 years ago
3 0
The charge on each of them is 0.173μC

Given the angle between the two  threads is 60° and the length of the two threads are equal.So, it forms an isoceles triangle so the other two angles will also be equal to 60°. Now,

Now, take a ball and we see that three forces act on it:

(i) Tension = T

(ii) Weight = mg

(iii) Electric force =  F (this will be replusive force because charges are same)

Tension T can be written as :

For equilibrium conditons, F = Tcos60°, mg = Tsin60°

Dividing, we get, \frac{F}{mg} = cot 60°

And we know, electric force , F = k\frac  {q^{2}}{r^{2}}

thus, q = \sqrt{ \frac{cot 60 . 9.8 . 0.20 * 10^{-3} * 0.25 }{9 * 10^{9} } 

          =  1.73 ×10^{-7}

         =  0.173μC

                                               

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1. A car travels a distance of 200 m in 4 seconds. What is the velocity of the car?
dybincka [34]

Answer:

velocity = distance / time taken

= 200/4

= 50 m/s

is the correct answer

3 0
3 years ago
The illustration in figure below shows a uniform metre rule weighing 30 N pivoted on a wedge placed under the 40 cm mark and car
Nitella [24]

Answer:

W = 30 N

Explanation:

Applying the summation of torques about the wedge for equilibrium, taking the clockwise direction as negative. Since the ruler is balanced horizontally about the wedge. Therefore, the summation of all torques acting about the wedge must be equal to zero.

(70\ N)(40\ cm - 10\ cm)-(30\ N)(50\ cm-40\ cm)-(W)(100\ cm - 40\ cm) = 0\\W(60\ cm) = (70\ N)(30\ cm)-(30\ N)(10\ cm)\\\\W = \frac{1800\ N.cm}{60\ cm}

<u>W = 30 N</u>

6 0
2 years ago
Alice and Bob are each riding horses on a carousel. Alice's horse is twice as far from the axis of spin of the carousel as Bob's
FromTheMoon [43]

Answer:

option (a)

Explanation:

the angular velocity of the carousel is same througout the motion, so the angular velocity of all the horses is same, but the linear velocity is different for different horses.

As the angular displacement of all the horses are same in the same time so the angular velocity is same.

The relation between the linear velocity and the angular velocity is given by

v = r ω

where, v is linear velocity and r be the distance between the horse and axis of rotation and ω be the angular velocity.

So, the angular velocity of Alice horse is same as the angular velocity of Bob horse.

ωA = ωB

Thus, option (a) is true.

8 0
3 years ago
1. A 14-cm tall object is placed 26 cm from a converging lens that has a focal length of 13 cm.
AURORKA [14]

Answer:

a) Please find attached the required drawing of light passing through the lens

By the use of similar triangles;

The image distance from the lens = 26 cm

The height of the image = 14 cm

c) The image distance from the lens = 26 cm

The height of the image = 14 cm

Explanation:

Question;

a) Determine the image distance and the height of the image

b) Calculate the image position and height

The given parameters are;

The height of the object, h = 14 cm

The distance of the object from the mirror, u = 26 cm

The focal length of the mirror, f = 13 cm

The location of the object = 2 × The focal length

Therefore, given that the center of curvature ≈ 2 × The focal length, we have;

The location of the object ≈ The center of curvature of the lens

The diagram of the object, lens and image created with MS Visio is attached

From the diagram, it can be observed, using similar triangles, that the image distance from the lens = The object distance from the lens = 26 m

The height of the image = The height of the object - 14 cm

b) The lens equation is used for finding the image distance from the lens as follows;

\dfrac{1}{u} + \dfrac{1}{v} = \dfrac{1}{f}

Where;

v = The image distance from the lens

We get;

v = \dfrac{u \times f}{u - f}

Therefore;

v = \dfrac{26 \times 13}{26 - 13} = \dfrac{26 \times 13}{13} = 26

The distance of the image from the lens, v = 26 cm

The magnification, M =v/u

∴ M = 26/26 = 1, therefore, the object and the image are the same size

Therefore;

The height of the image = The height of the object = 14 cm.

5 0
2 years ago
What color will a star be with a surface temperature of 5000 6000 K?
11Alexandr11 [23.1K]
The color of a star would with that surface temperature would be White. Hope this helps. :)
6 0
3 years ago
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