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Alex17521 [72]
2 years ago
15

Two identical balls balls P and Q, each of mass 0.20 g, carry identical charges and are suspended by two threads of equal length

. The balls position themselves at equilibrium such that the angle between the threads is 60_{o}.If the distance between the the balls is 0.5m, find the charge on each of them. Take g = 9.8 m/s^{2}

Physics
1 answer:
Elden [556K]2 years ago
3 0
The charge on each of them is 0.173μC

Given the angle between the two  threads is 60° and the length of the two threads are equal.So, it forms an isoceles triangle so the other two angles will also be equal to 60°. Now,

Now, take a ball and we see that three forces act on it:

(i) Tension = T

(ii) Weight = mg

(iii) Electric force =  F (this will be replusive force because charges are same)

Tension T can be written as :

For equilibrium conditons, F = Tcos60°, mg = Tsin60°

Dividing, we get, \frac{F}{mg} = cot 60°

And we know, electric force , F = k\frac  {q^{2}}{r^{2}}

thus, q = \sqrt{ \frac{cot 60 . 9.8 . 0.20 * 10^{-3} * 0.25 }{9 * 10^{9} } 

          =  1.73 ×10^{-7}

         =  0.173μC

                                               

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The coulombic force between two ions is reduced to ______ of its original strength when the distance between them is quadrupled.
gayaneshka [121]

Answer:

<h3>1/16</h3>

Explanation:

According to the coulombs law, the force existing vetween the ions is expressed as;

F = kQq/r² .... 1

Q and q are the ions

r is the distance between the ions

If the distance between the ion is quadrupled, then;

F2 =  kQq/(4r)²

F2 =  kQq/16r² ... 2

Divide equation 2 by 1;

F2/F = kQq/16r² ÷ kQq/r²

F2/F = kQq/16r² × r²/kQq

F2/F = 1/16

F2 = 1/16 F

Therefore the coulombic force between two ions is reduced to<u> 1/16 </u>of its original strength when the distance between them is quadrupled.

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3 years ago
A Smart Car, which has a mass of 1000 kg, is going 20 m/s. When it hits the barrier, it stops with a time of 0.5 seconds. What i
antiseptic1488 [7]

Answer:

The change in momentum = -20000 kg m/s.

Explanation:

Mass m = 1000 kg

speed v₁ = 20 m/s

speed v₂ = 0 m/s

We know that,

The change in momentum

ΔP = m (Δv)

ΔP = m (v₂ - v₁)

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     = 1000 (-20)

     = -20000 kg m/s

Thus, the change in momentum = -20000 kg m/s.

Note: negative sign indicates that the velocity is reducing when it hits the barrier.

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2 years ago
True or false mechanical waves need a medium through which to transport energy
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Answer:True

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Answer:

It can be seen from the operation of pin-hole camera, formation of shadows and eclipse.

Explanation:

The phenomenon of light traveling in a straight line is known as rectilinear propagation of light.

One this evidence can be seen from the operation of pin-hole camera, which depends on rectilinear propagation of light

Also two natural effects that result from the rectilinear propagation of light are the formation of Shadows and Eclipse.  

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2 years ago
Two boats leave the same port at the same time, with boat A traveling north at 15 knots (nautical miles per hour) and boat B tra
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Answer:

The chance in distance is 25 knots

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s^2 = (x_A - x_B)^2+(y_A - y_B)^2  (1)

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s^2 = x_B^2+y_A^2 (2)

Taking the differential with respect to time:

\displaystyle{2s\frac{ds}{dt}= 2x_B\frac{dx_B}{dt}+2y_A\frac{dy_A}{dt}}  (3)

where \displaystyle{\frac{dx_B}{dt}}=v_B and \displaystyle{\frac{dx_A}{dt}}=v_A are the respective given velocities of the boats. To find s and x_B we make use of the given position for A, y_A=30, the Pythagoras theorem and the relation between distance and velocity for a movement with constant velocity.

\displaystyle{y_A = v_A\cdot t\rightarrow t = \frac{y_A}{v_A}=\frac{30}{15}=2 h

with this time, we know can now calculate the distance at which B is:

\displaystyle{x_B = v_B\cdot t= 20 \cdot 2 = 40\ nmi

and applying Pythagoras:

\displaystyle{s = \sqrt{x_B^2+y_A^2}=\sqrt{30^2 + 40^2}=\sqrt{2500}=50}

Now substituting all the values in (3) and solving for  \displaystyle{\frac{ds}{dt} } we get:

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