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aleksklad [387]
3 years ago
8

Assuming that a2 is the magnitude of the horizontal acceleration of the block of mass m2, what is T, the tension in the string

Physics
1 answer:
cestrela7 [59]3 years ago
6 0

Answer:

T= (m2a2)/2

Explanation:

Using Newton's second law

F21+F22+ F33.....= M2a2

Where F21 and F22 are forces acting on M2

Thus T = ( M2a2)/2 this is tension on the string

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An object is thrown straight up with an initial velocity of 10 m/s, and there is an air resistance force causing an acceleration
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Answer:

Vf= 7.29 m/s

Explanation:

Two force act on the object:

1) Gravity

2) Air resistance

Upward motion:

Initial velocity = Vi= 10 m/s

Final velocity = Vf= 0 m/s

Gravity acting downward =  g = -9.8 m/s²

Air resistance acting downward = a₁ = - 3 m/s²

Net acceleration = a = -(g + a₁ ) = - ( 9.8 + 3 ) = - 12.8 m/s²

( Acceleration is consider negative if it is in opposite direction of velocity )

Now

2as = Vf² - Vi²

⇒ 2 * (-12.8) *s = 0 - 10²

⇒-25.6 *s = -100

⇒ s = 100/ 25.6

⇒ s = 3.9 m

Downward motion:

Vi= 0 m/s

s = 3.9 m

Gravity acting downward =  g = 9.8 m/s²

Air resistance acting upward = a₁ = - 3 m/s²

Net acceleration = a = g - a₁  =  9.8 - 3  = 6.8 m/s²

Now

2as = Vf² - Vi²

⇒ 2 * 6.8 * 3.9 = Vf² - 0

⇒ Vf² = 53. 125

⇒ Vf= 7.29 m/s

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3 years ago
Explain why pulleys are in the lever family.
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Answer:

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Answer:

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Explanation:

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s344n2d4d5 [400]

Answer:

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