Assuming that a2 is the magnitude of the horizontal acceleration of the block of mass m2, what is T, the tension in the string
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Hi there!
We can begin by calculating the time the ball takes to reach the highest point of its trajectory, which can be found using the following:
Where:
tmax = (? sec)
vsinθ = vertical comp. of velocity = 10sin(48) = 7.43 m/s)
g = acceleration due to gravity (9.8 m/s²)
We can solve for this time:
When the ball is at the TOP of its trajectory, its VERTICAL velocity is equivalent to 0 m/s. Thus, we can consider this a free-fall situation.
We must begin by solving for the maximum height reached by the ball using the equation:
d = displacement (m)
vi = initial velocity (7.43 m/s)
a = acceleration due to gravity
d = displacement (m)
y0 = initial VERTICAL displacement (28m)
Plug in the values:
Now, we can use the rearranged kinematic equation:
Add the two times together:
Answer:
The value is
Explanation:
From the question we are told that
The mass is
The length is
The angle is
The damping constant is
The time taken is
Generally the angular frequency of this damped oscillation is mathematically evaluated as
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Generally the period of the oscillation is mathematically represented as
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Generally the number of oscillation is mathematically represented as
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