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3 years ago

Question 19: Solve for X.

Mathematics

1 answer:

Vlad1618 [11]3 years ago

6 0

Answer:

$19 \100 \times x =$

$1900$

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Answer:
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3 years ago

f(x) = -4x^2+12x-9f(x)=−4x 2 +12x−9f, left parenthesis, x, right parenthesis, equals, minus, 4, x, squared, plus, 12, x, minus,

Olin [163]

Answer:

The graph has only one x-intercept

Step-by-step explanation:

we have

$f(x)=-4x^2+12x-9$

we know that

The discriminant of a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$D=b^{2}-4ac$

in this problem we have

$f(x)=-4x^2+12x-9$

$a=-4\\b=12\\c=-9$

substitute

$D=12^{2}-4(-4)(-9)$

$D=144-144$

$D=0$

The discriminant is zero

That means ----> The quadratic equation has one real solution

The graph has only one x-intercept

3 0

3 years ago

The equation of a circle is given below. x^{2}+(y-2.25)^{2} = \dfrac{196}{169}x 2 +(y−2.25) 2 = 169 196 x, squared, plus, left

Lostsunrise [7]

Center = $(h,k) = (0,2.25)$
Radius = $r = \frac{14}{13}$

<u>Step-by-step explanation:</u>

Here we have following equation : $x^{2}+(y-2.25)^{2} = \dfrac{196}{169}$

We need to find the center & radius of this circle . Let's find out:

We know that , Equation of a circle is given by :

⇒ $(x-h)^2+(y-k)^2=r^2$ ........(1)

Here , (h,k) are the co-ordinates of center & r is the radius of circle.Collectively called as a circle with radius r and center at (h,k) . Let's frame given equation in question :

⇒ $x^{2}+(y-2.25)^{2} = \frac{196}{169}$

⇒ $(x-0)^{2}+(y-2.25)^{2} = (\frac{14}{13})^2$

On comparing this equation with equation (1) we get :

Center = $(h,k) = (0,2.25)$
Radius = $r = \frac{14}{13}$

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