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LekaFEV [45]
3 years ago
6

The ticket sales for a concert started at 4:00 P.M. The table shows the linear relationship

Mathematics
1 answer:
Vadim26 [7]3 years ago
4 0

Answer: J. for people in Ed or  y = -3,000x + 15,000

Step-by-step explanation:

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2x + 2y = 2, 2(x + y) = 10}
Dima020 [189]
X will equal 5
y will equal 0
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4 years ago
Write the equation of a line in point-slope form that is parallel to the line y = 3x +6 and passes through the point (-5, 8).
alexandr1967 [171]
Slope = 3
(-5, 8)

y - 8 = 3 (x + 5)
this is point slope form

y - 8 = 3x + 15
y = 3x + 23
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3 years ago
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Find the area of the square.<br> 2/7m
sasho [114]

Answer:

Step-by-step explanation:

if you have one side =2/7

area = (2/7)^2=4/49 m^2

8 0
3 years ago
a rectangle has a perimeter of 68 inches.if the width of the rectangle is 10 inches,what is the length of the rectangle?
Dmitriy789 [7]

Answer:

l=24in

Step-by-step explanation:

P=2(l+w)

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3 years ago
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A sample of a radioactive isotope had an initial mass of 360 mg in the year 1998 and
RUDIKE [14]

Answer:

193 mg

Step-by-step explanation:

Exponential decay formula:

  • A_t = A_0e^r^t
  • where Aₜ = mass at time t, A₀ = mass at time 0,  r = decay constant (rate), t = time  

Our known variables are:

  • 1998 to the year 2004 is a total of t = 6 years.
  • The sample of radioactive isotope has an initial mass of A₀ = 360 mg at time 0 and a mass of Aₜ = 270 mg at time t.

Let's solve for the decay constant of this sample.

  • 270=360e^-^r^(^6^)
  • 270=360e^-^6^r
  • \frac{3}{4} =e^-^6^r
  • \text{ln} (\frac{3}{4} )= \text{ln}(e^-^6^r)
  • \text{ln} (\frac{3}{4} )=-6r
  • r=-\frac{\text{ln}\frac{3}{4} }{6}
  • r=0.04794701

Using our new variables, we can now solve for Aₜ at t = 7 years, since we go from 2004 to 2011.

Our new initial mass is A₀ = 270 mg. We solved for the decay constant, r = 0.04794701.

  • A_t=270e^-^(^0^.^0^4^7^9^4^8^0^1^)^(^7^)
  • A_t=270e^-^0^.^3^3^5^6^2^9^0^7
  • A_t=193.01982213

The expected mass of the sample in the year 2011 would be 193 mg.

3 0
3 years ago
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