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3 years ago

What requirements exist for a molecule to be polar?

Chemistry

1 answer:

Mama L [17]3 years ago

7 0

Answer:

for a molecule to be polar to conditions must be met one we must have at least one polar bond or one lone pair on the central atom to if there are more than one polar bond they must be arranged in a way that their dipoles do not cancel

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I need to know the measurements of this to the appropriate amount of significant figures

Vesnalui [34]

Answer:

[See Below]

Explanation:

140 ml.

3 0

3 years ago

scZoUnD [109]

Answer:

A.) Linear

Explanation:

4 0

3 years ago

12. Contrast the movement of charges in a

nikdorinn [45]

DEEZ NUTS ha gattti -sorry

4 0

3 years ago

Question 2 (0 points)

bazaltina [42]

Answer:

The probability of spinning red with the spinner or rolling an odd number with the die is $\dfrac{1}{8}$

Explanation:

Given that,

Total color in spinner = 4

Let the area of four parts is equal in the spinner.

We need to calculate the probability of spinning red

Using formula of probability

$P(A) = \dfrac{Number\ of\ red\ color\ outcome}{Total\ number\ of\ colors\ in\ the\ spinner}$

Put the value into the formula

$P(A)=\dfrac{1}{4}$

We need to calculate the probability of odd number of the die

Using formula of probability

$P(B) = \dfrac{Number\ of\ odd\ digits\ outcome}{Total\ number\ of\ digits\ in\ the\ die}$

Put the value into the formula

$P(B)=\dfrac{3}{6}$

$P(B)=\dfrac{1}{2}$

We need to calculate the probability of spinning red with the spinner or rolling an odd number with the die

Using formula of probability of two events which is independent

$P(A\ and\ B)=P(A)\times P(B)$

Put the value into the formula

$P(A\ and\ B)=\dfrac{1}{4}\times\dfrac{1}{2}$

$P(A\ and\ B)=\dfrac{1}{8}$

Hence, The probability of spinning red with the spinner or rolling an odd number with the die is $\dfrac{1}{8}$

5 0

3 years ago

Chem help<br>calculate the wavelength of an electromagnetic wave with a frequency of (in pic)

olchik [2.2K]

we have,

wavelenght=c/f

where c= 3×10^8 m/s

f=6.3×10^12 s^-1

so wavelength=(3×10^8)/(6.3×10^12)

=0.476×10^-4 m

4 0

3 years ago