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Allisa [31]
3 years ago
12

Which is an important step in the alternate method for balancing equations in redox reactions?

Chemistry
2 answers:
Gennadij [26K]3 years ago
7 0

Answer:

C....  - Determining the half reactions of chemical equations

Explanation:

Try It... -

Whitepunk [10]3 years ago
6 0

Answer:

the answer is C

Explanation:

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C. no difference in the electronegativity of oxygen and hydrogen
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Write an algebraic expression to repro<br> 1.4 times a number, increased by 7
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I think its gonna be 5
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3 years ago
4.
telo118 [61]

The series which is in order of increasing boiling point is CH3CH2CH3 CH3COCH3 CH2CH2CH3OH

However, the boiling point of an organic substance is the temperature at which the vapor pressure of the liquid organic substance equals the pressure surrounding the liquid and the liquid changes into a vapor.

<h3>What are organic compounds?</h3>

Organic compounds are substance containing carbon and hydrogen. Some few organic compounds include:

  • Alkanes
  • Alkenes
  • Alkynes
  • Alkanols
  • Alkanals
  • Alkanones
  • Esters
  • Amines

So therefore, the series which is in order of increasing boiling point is CH3CH2CH3 CH3COCH3 CH2CH2CH3OH

Learn more about organic compounds:

brainly.com/question/704297

8 0
2 years ago
Why is most of the Earth’s fresh water unavailable?
lisov135 [29]

Answer:

2.5% of the earth's fresh water is unavailable: locked up in glaciers, polar ice caps, atmosphere, and soil; highly polluted; or lies too far under the earth's surface to be extracted at an affordable cost.

Explanation:

3 0
3 years ago
What is the half-life of a pharmaceutical if the initial dose is 500 mg and only 31 mg remains after 6 hours?
Sergeu [11.5K]

Answer:

\large \boxed{\text{b. 1.5 h}}

Explanation:

1. Calculate the rate constant

The integrated rate law for first order decay is

\ln \left (\dfrac{A_{0}}{A_{t}}\right ) = kt

where

A₀ and A_t are the amounts at t = 0 and t

k is the rate constant

\begin{array}{rcl}\ln \left (\dfrac{500}{31}\right) & = & k \times 6\\\\\ln 16.1 & = & 6k\\2.78& =& 6k\\k & = & \dfrac{2.78}{6}\\\\& = & 0.463 \text{ h}^{-1}\\\end{array}

2. Calculate the half-life

t_{\frac{1}{2}} = \dfrac{\ln2}{k} = \dfrac{\ln2}{\text{0.463  h}^{-1}} = \textbf{1.5 h}\\\\ \text{The half-life is $\large \boxed{\textbf{1.5 h}}$}

4 0
3 years ago
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