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liubo4ka [24]
3 years ago
11

Which of the following describes air pressure?

Chemistry
1 answer:
ira [324]3 years ago
4 0

Answer:

the weight of the atmosphere pressing down on Earth

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Which of these elements is essential to making up all of the organic molecules?
siniylev [52]
Carbon

Hope this helps (:
5 0
3 years ago
Read 2 more answers
Using the Hoffman apparatus for electrolysis, a chemist decomposes 2.3 moles of water into its gaseous elements. How many grams
solong [7]

Answer:

2.318032g

Explanation:

-The electrolysis equation of water is written as below:

2H_2O_{(l)}->2H_2_{(g)}+O_2_{(g)}

-The mole ratio of Water to the hydrogen formed is 1:1, therefore 2.3 moles of hydrogen gas is produced.

-Hydrogen's molar mass is 1.00784 grams:

Mass=moles\times molar \ mass\\\\\=2.3\times 1.00784\\\\=2.318032\ g

Hence, 2.318032 grams of hydrogen is produced.

7 0
3 years ago
What mass of water is produced by the combustion 1.2 x 10^26 molecules of butane ?
podryga [215]

Answer:

17.934 kg of water

Explanation:

If balanced equation is not given; this format can come in handy.

For any alkane of the type : CₙH₂ₙ₊₂ , it's combustion reaction will follow:

2CₙH₂ₙ₊₂ + (3n+1) O₂  →  (2n)CO₂ + 2(n+1) H₂O

For butane:

2C₄H₁₀(g) + 13O₂(g) →  8CO₂(g) + 10H₂O(l)

2 moles of butane gives 10 moles of water.

1 mol of any substance has Avogadro number(N) of molecules in it( 6.022 x 10²³)

Mass of 1 mole of any substance is equal to it's molar mass

So, if 2 x N molecules of butane gives 10 x 18 g of water.

Then  1.2 x 10²⁶ molecules will give:

\frac{1.2 \times 10^{26} \times 180}{2 \times 6.022 \times  10^{23}}

= 17.934 x 10³ g of water

= 17.934 kg of water

5 0
3 years ago
Boyle's Law states that when a sample of gas is compressed at a constant temperature, the pressure P and volume V satisfy the eq
ad-work [718]

Answer:

-75 cm^3/min

Explanation:

Given from Boyle's law;

PV=C

From product rule;

VdP/dt + PdV/dt = dC/dt

but dC/dt = 0, V= 500 cm^3, P= 200kPa, dP= 30kPa/min

PdV/dt = dC/dt - VdP/dt

dV/dt = dC/dt - VdP/dt/ P

substituting values;

dV/dt = 0 - (500 * 30)/200

dV/dt = -75 cm^3/min

5 0
2 years ago
Someone help1!1!1!1!!!!!
alisha [4.7K]
The question is cut off in the picture
7 0
3 years ago
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