Answer:
Temperature after ignition=7883.205 K
Explanation:
The number of moles is,
n=PV/RT
=(1.18x10^6)(47.9x10^-6)/8.314(325)
= 0.0209 moles
a) In this process volume is constant
Q=U
=nCv.dT
dT= Q/nCv
=1970/(1.5x8.314)(0.0209)
= 7558.205 K
The final temperature is,
= 7558.205+325
= 7883.205 K
The amount of energy in the universe is remaining constant .
So , option (D) is right ..
Answer:
In case of electrostatic force, the work done is independent of path, it only depends on the final and initial positions of the charge. This path independent nature makes electrostatic force a conservative force. Thus, the option a becomes true, and the opposite statement (ie.
Answer:
The peak emf generated by the coil is 418.3 mV
Explanation:
Given;
number of turns, N = 980 turns
diameter, d = 11 cm = 0.11 m
magnetic field, B = 5 x 10⁻⁵ T
time, t = 7 ms = 7 x 10⁻³ s
peak emf, V₀ = ?
V₀ = NABω
Where;
N is the number of turns
A is the area
B is the magnetic field strength
ω is the angular velocity
V₀ = NABω and ω = 2πf = 2π/t
V₀ = NAB2π/t
A = πd²/4
V₀ = N x (πd²/4) x B x (2π/t)
V₀ = 980 x (π x 0.11²/4) x 5 x 10⁻⁵ x (2π/0.007)
V₀ = 980 x 0.00951 x 5 x 10⁻⁵ x 897.71
V₀ = 0.4183 V = 418.3 mV
The peak emf generated by the coil is 418.3 mV
Answer:
u_o = 12.91 m/s
Explanation:
Given:
- mass of the ball m = 0.15 kg
- Spacing between each equipotential line s = 1.0 m
- Charge on the ball is q = 10 mC
Find:
- What initial velocity must it have at the 200-V level for it to reach its maximum height at the 700-V level
Solution:
- Notice that the Electric field lines are directed from Higher potential to lower potential i.e V = + 700 level to V = 200 level. The gravitational acceleration also acts downwards.
- We will compute a resultant acceleration due to gravity and Electric Field as follows:
g' = g + F_e / m
- Where F_e is the Electrostatic Force given by:
F_e = E*q
- Electric field strength is given by:
E = V / d
- Hence,
g' = g + (dV*q/ d*m)
- Input values:
g' = 10 + (500*10^-2 / 5*0.15)
g' = 16.6667 m/s^2
- Now use one of the equation of motions in y-direction:
h_max = u_o ^2 / 2*g'
- Input values where h_max = 5 m
5*2*g' = u_o ^2
u_o = sqrt (166.667)
u_o = 12.91 m/s
